A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large{x^24x12=0}\] right?

ProgramGuru
 2 years ago
Best ResponseYou've already chosen the best response.1you just add 4 to both sides. that will make it \[(x2)^{2}=16\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2ok so now .. \[\large{x^24x12=x^24x+416=0}\] right?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2now can u write \[\large{x^24x+4=(x2)^2}\] ??

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2(x)^2 2(2)(x)+2^2 = a^22ab+b^2=(ab)^2=(x2)^2

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2ok so : (x^24x+4) = (x2)^2 ?

gfields444
 2 years ago
Best ResponseYou've already chosen the best response.0x^24x12=0 x=2 x=6? or am I doing it wrong

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2I think you are doing it wrong ; : x^24x12 = 0 \[\large{x^24x+416=0}\] \[\large{(x2)^216=0}\] \[\large{(x24)(x2+4)=0}\] \[\large{(x6)(x+2)=0}\] hence either x = 6 or x = 2

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2always remember that : \[\large{(ab)^2=a^22ab+b^2}\] \[\large{(a+b)^2=a^2+2ab+b^2}\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2or : \[\large{(a\pm b)^2=a^2\pm 2ab +b^2}\]

gfields444
 2 years ago
Best ResponseYou've already chosen the best response.0You're awesome! Thank you so much! The formulas were very helpful :)

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2nice to hear .. :) best of luck
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.