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CesarLovesNadia Group Title

find the amount of time in years that it will take an investment of $1000 to double at 8%interest compounded continuosly. (hint A=Pe^rt

  • 2 years ago
  • 2 years ago

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  1. cshalvey Group Title
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    Hi @CesarLovesNadia - so you know the formula you need to use, correct? Are you able to put them together?

    • 2 years ago
  2. CesarLovesNadia Group Title
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    no im not thats why its here i need help

    • 2 years ago
  3. cshalvey Group Title
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    No problem, so the interest formula for compound interest is what you have listed. So, A is the number we are looking for, we have the rest. So, A = P (principal amount) x e (Napier's #, roughly 2.7183) ^ r (interest rate) x t (number of years). So, how about you try and put in the numbers you know, and I can help you with anything you don't understand?

    • 2 years ago
  4. cshalvey Group Title
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    For the 'e' - your calculator will actually have this number built in, so don't worry about it for now :)

    • 2 years ago
  5. CesarLovesNadia Group Title
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    so whats the answer?

    • 2 years ago
  6. CesarLovesNadia Group Title
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    how many years would it be?

    • 2 years ago
  7. cshalvey Group Title
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    @CesarLovesNadia - You have to learn how to do these problems - I'm not here to give you the answer. I WILL help you get there though, I promise. Can you try and put the variables from the word problem into the equation now?

    • 2 years ago
  8. CesarLovesNadia Group Title
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    i diid i put 1000*2.7183^(0.08*1)

    • 2 years ago
  9. CesarLovesNadia Group Title
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    it came out to be like 1000 something

    • 2 years ago
  10. cshalvey Group Title
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    No worries - and good start. The problem states that you need to find the time, t, for your money to double. Therefore, you know that A = 2xP = 2000. So, your equation looks like this: \[2000 = 1000*e^(.08*t)\]

    • 2 years ago
  11. CesarLovesNadia Group Title
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    so then wait

    • 2 years ago
  12. CesarLovesNadia Group Title
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    the answer would be 2000 then?

    • 2 years ago
  13. ParthKohli Group Title
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    Colm, it'd be \(2000 = 1000 \times e^{(0.8 \times t)}\) Sorry for interfering, guys.

    • 2 years ago
  14. CesarLovesNadia Group Title
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    thanks

    • 2 years ago
  15. ParthKohli Group Title
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    @CesarLovesNadia You should appreciate Colm for helping you :) P.S. He's the major part behind OpenStudy ;)

    • 2 years ago
  16. cshalvey Group Title
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    Heh, that's what I was writing - guess it showed up wrong. And no, @CesarLovesNadia you need to find the TIME, t in this equation, right? "find the amount of time in years"

    • 2 years ago
  17. CesarLovesNadia Group Title
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    but what is it then?

    • 2 years ago
  18. CesarLovesNadia Group Title
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    just help me and give me the answer

    • 2 years ago
  19. cshalvey Group Title
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    @CesarLovesNadia - sorry, but you should read the Code of Conduct (http://openstudy.com/code-of-conduct) - we don't just give the answer. I can help you understand it though :) So now, you have to solve for T in that equation I and Parth just gave you. Can you start that?

    • 2 years ago
  20. CesarLovesNadia Group Title
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    so would it be 2?

    • 2 years ago
  21. CesarLovesNadia Group Title
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    is it 2?

    • 2 years ago
  22. ParthKohli Group Title
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    Heh—don't give me the credit. Keep it on, guys!

    • 2 years ago
  23. CesarLovesNadia Group Title
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    help me with another one

    • 2 years ago
  24. cshalvey Group Title
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    Given your equation 2000 = 1000 x e^(.08xT) We divide both sides by 1000 to give us this: 2 = e^(.08xT)

    • 2 years ago
  25. ParthKohli Group Title
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    Wolfram time! http://www.wolframalpha.com/input/?i=e%5E%280.8t%29+%3D+2

    • 2 years ago
  26. ParthKohli Group Title
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    Your Math is pretty good, Colm!

    • 2 years ago
  27. cshalvey Group Title
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    @CesarLovesNadia - you'll probably want to use that link to get the real answer. Hint - it's not two.

    • 2 years ago
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