A community for students.
Here's the question you clicked on:
 0 viewing
GiggleSquid
 3 years ago
Need your help again rkfitz053!
GiggleSquid
 3 years ago
Need your help again rkfitz053!

This Question is Closed

GiggleSquid
 3 years ago
Best ResponseYou've already chosen the best response.0trying to write it in standard form. i got 4(x^28x) + (y^212y)=36 so far

rkfitz053
 3 years ago
Best ResponseYou've already chosen the best response.1Start by gathering all like terms so the equation looks like this (you got this one.):\[4x^28x+y^212y=36\] Then start by completing the square (take 1/2 of the coefficient on the x term and square that, then add it to the end, make sure you also add it to the right side. And multiply that 4 to the 1 you added) for the x terms and the y terms: \[4(x^2+2x+1)+(y^212y+36)=4\] Now you have two perfect square trinomials and you can factor those and divide all terms by 4 to end up with: \[(x+1)^2  (y6)^2/4=1\] Can you figure out the centre from there?

GiggleSquid
 3 years ago
Best ResponseYou've already chosen the best response.0ya its 1,6 right? thanks!

rkfitz053
 3 years ago
Best ResponseYou've already chosen the best response.1The trickiest part is always remembering to multiply what you add by the factor that you took out before (multiplying 4 to 1 when completing the sq)

GiggleSquid
 3 years ago
Best ResponseYou've already chosen the best response.0how do i find the vertices? i'm better with ellipses :/

rkfitz053
 3 years ago
Best ResponseYou've already chosen the best response.1Your vertices are going to be a distance of 'a' away from the center. Remember the std eqn for hyperbolas: \[x^2/a^2y^2/b^2=1\] so you just have to take the sqrt of what the first term is divided by. In your question a^2=1

rkfitz053
 3 years ago
Best ResponseYou've already chosen the best response.1The foci are almost the same as ellipses too...it's just \[c=\sqrt{a^2+b^2}\] They're added now because the foci points are on the outside of the vertices, rather than inside an ellipse.

rkfitz053
 3 years ago
Best ResponseYou've already chosen the best response.1Vertices are the same as ellipses and foci you add instead of subtract.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.