## hali12 3 years ago pentagon ABCDE ~ pentagon FGHIJ. Use the figures below to answer the following questions @jim_thompson5910

1. jim_thompson5910

you're missing the figures

2. jim_thompson5910

or the following questions

3. hali12

sorry i keep getting distracted

4. jim_thompson5910

that's ok

5. jim_thompson5910

AB corresponds to FG

6. jim_thompson5910

So FG/AB = 6/8 = 0.75 is the number you multiply each side length in the larger pentagon to get the corresponding side length in the smaller pentagon

7. hali12

8?

8. jim_thompson5910

8 times 0.75 = 6

9. jim_thompson5910

oh wait, i read that wrong...one sec

10. jim_thompson5910

oh for some reason, it still works out...lucky coincidence but yes, you multiply by 0.75

11. hali12

oh

12. jim_thompson5910

to go backwards, you divide by 0.75

13. jim_thompson5910

notice how FJ corresponds to AE

14. jim_thompson5910

and FJ = 6 So AE = FJ/0.75 = 6/0.75 = 8 which means AE = 8

15. hali12

so then i had it right?

16. jim_thompson5910

yes, sry i didn't see that til now

17. hali12

ok, cool and for #14 it would be 2.5?

18. hali12

no no no it would be 3

19. jim_thompson5910

which side corresponds to IJ?

20. hali12

CD, so it would make it 3? correct?

21. jim_thompson5910

this is why this problem is a bit confusing

22. jim_thompson5910

the second pentagon should be rotated slightly clockwise so that FG matches up with AB

23. jim_thompson5910

now tell me what ij corresponds to

24. hali12

8

25. jim_thompson5910

did you do the rotation? this will make F the bottom most point

26. hali12

yea

27. jim_thompson5910

so ij corresponds to ???

28. jim_thompson5910

which side from ABCDE

29. hali12

de

30. jim_thompson5910

good

31. jim_thompson5910

now multiply that length by 0.75 to find ij

32. hali12

2.5

33. jim_thompson5910

try it again 5 times 0.75 = ???

34. jim_thompson5910

de = 5

35. hali12

3.75

36. jim_thompson5910

good

37. hali12

fg would be 4?

38. jim_thompson5910

fg corresponds to ???

39. hali12

ab?

40. jim_thompson5910

good FG = 0.75 times AB

41. hali12

6

42. jim_thompson5910

you nailed it

43. hali12

thanks, this will be the last one i promise

44. jim_thompson5910

The two triangles are similar So AD/ED = BD/CD 35/16 = 25/x Now solve for x

45. hali12

9.6?

46. jim_thompson5910

no

47. jim_thompson5910

35/16 = 25/x 35x = 16*25

48. hali12

7 6/7

49. jim_thompson5910

no it's not any of those answer choices

50. jim_thompson5910

x is the length of CD

51. jim_thompson5910

which isn't listed

52. hali12

16*25=400

53. jim_thompson5910

good

54. jim_thompson5910

35x = 16*25 35x = 400

55. hali12

dfsdfdddddddd

56. hali12

sorry cat walked on the kep board... and i dont get wat i do next

57. hali12

key*

58. jim_thompson5910

that's ok, divide both sides by 35

59. hali12

45 divided by 35, and what else by 35?

60. hali12

11.4

61. jim_thompson5910

ok now subtract this from 25

62. hali12

13.6

63. jim_thompson5910

which is closest to which answer choice?

64. hali12

13 4/7

65. hali12

13.6 is closest to 13 6/7

66. jim_thompson5910

67. jim_thompson5910

13.6 is closest to 13 4/7

68. jim_thompson5910

69. hali12

13 4/7

70. jim_thompson5910

yes

71. hali12

thank you,... i was just wondering, but are u like a teacher or something?

72. jim_thompson5910

i'm a student learning to become one

73. hali12

74. jim_thompson5910

why thank you, i appreciate the compliment

75. hali12

your are verry verry welcome, you helped me out so much that i officaly have a B in geometry ( summerschool) i had failed it the first time idurring the year, i dont know what i would have done with out you...

76. jim_thompson5910

i'm glad i could help you out, you're very smart and it sounds like you're starting to get the hang of this stuff, which is great

77. hali12

thank you :)

78. jim_thompson5910

you're welcome