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Kija_Destiny_Lee

  • 3 years ago

Okay so I'm working on proofs with congruent triangles and I'm stuck on one of them: 3. Given: D is the midpoint of AC, angle BDC is congruent to DBA Prove: angle ABD is congruent to CBD

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  1. Kija_Destiny_Lee
    • 3 years ago
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  2. Kija_Destiny_Lee
    • 3 years ago
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    We got D is the midpoint of AC and BDC is congruent to BDA which both ar e given. We just need one more.

  3. Hashir
    • 3 years ago
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    BD is common and equal in both of them .... secondly AD=DC since the two sides are equal in both the triangle ...and both are right angled ... thus .. hypotenuse must also be equal ..as a result they are congruent by SSS property

  4. Kija_Destiny_Lee
    • 3 years ago
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    oh okay thank you lots ;)

  5. Hashir
    • 3 years ago
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    my pleasure :)

  6. Kija_Destiny_Lee
    • 3 years ago
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    okay so you are sayin that AD=DC are SSS right? r are those two different things?

  7. Hashir
    • 3 years ago
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    noooo .. they are the same .....AD = DC because .... d is the midpt ... sss means ... side side side property

  8. Hashir
    • 3 years ago
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    that is all the three sides are equal

  9. Kija_Destiny_Lee
    • 3 years ago
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    oh okay i get it now ;)

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