Okay so I'm working on proofs with congruent triangles and I'm stuck on one of them: 3. Given: D is the midpoint of AC, angle BDC is congruent to DBA Prove: angle ABD is congruent to CBD

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We got D is the midpoint of AC and BDC is congruent to BDA which both ar e given. We just need one more.

BD is common and equal in both of them .... secondly AD=DC since the two sides are equal in both the triangle ...and both are right angled ... thus .. hypotenuse must also be equal ..as a result they are congruent by SSS property

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