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Kija_Destiny_Lee

Okay so I'm working on proofs with congruent triangles and I'm stuck on one of them: 3. Given: D is the midpoint of AC, angle BDC is congruent to DBA Prove: angle ABD is congruent to CBD

  • one year ago
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  1. Kija_Destiny_Lee
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    • one year ago
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  2. Kija_Destiny_Lee
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    We got D is the midpoint of AC and BDC is congruent to BDA which both ar e given. We just need one more.

    • one year ago
  3. Hashir
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    BD is common and equal in both of them .... secondly AD=DC since the two sides are equal in both the triangle ...and both are right angled ... thus .. hypotenuse must also be equal ..as a result they are congruent by SSS property

    • one year ago
  4. Kija_Destiny_Lee
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    oh okay thank you lots ;)

    • one year ago
  5. Hashir
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    my pleasure :)

    • one year ago
  6. Kija_Destiny_Lee
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    okay so you are sayin that AD=DC are SSS right? r are those two different things?

    • one year ago
  7. Hashir
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    noooo .. they are the same .....AD = DC because .... d is the midpt ... sss means ... side side side property

    • one year ago
  8. Hashir
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    that is all the three sides are equal

    • one year ago
  9. Kija_Destiny_Lee
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    oh okay i get it now ;)

    • one year ago
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