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qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.0What's going on with y as x keeps getting bigger?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Why growth?\[0.05^2 <0.05^1 \]That proves that it's decay itself.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1If the second power is less than the first, then we have an exponential decay. Get it?

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.0Yes, I believe the OP means raised to the power of x. Not linear in x.

Hashir
 2 years ago
Best ResponseYou've already chosen the best response.0if its a raised power then may be its decay

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1@Hashir The question is\[5 \times 0.5^x\]

qpHalcy0n
 2 years ago
Best ResponseYou've already chosen the best response.0Well, if its raised to x, its DEFINITELY decay, not maybe.

greener6
 2 years ago
Best ResponseYou've already chosen the best response.0so if the number in the parentheses is lower then 1 its decay

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1When people copy and paste questions, they don't type out ^ before powers.

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0\[y(x) = 5(0.5)^x\] lets try some points \[y(0) = 5(0.5)^0=5\] \[y(1) = 5(0.5)^1=5\times0.5=2.5\] \[y(2) = 5(0.5)^2=5\times0.25=1.25\] as x goes up y decreases , decay

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1343887585554:dw

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1343887677903:dw
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