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greener6 Group Title

Is the equation y = 5(0.5)x an example of growth or decay?

  • one year ago
  • one year ago

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  1. Hashir Group Title
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    |dw:1343887344705:dw|

    • one year ago
  2. qpHalcy0n Group Title
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    What's going on with y as x keeps getting bigger?

    • one year ago
  3. ParthKohli Group Title
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    Why growth?\[0.05^2 <0.05^1 \]That proves that it's decay itself.

    • one year ago
  4. ParthKohli Group Title
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    If the second power is less than the first, then we have an exponential decay. Get it?

    • one year ago
  5. qpHalcy0n Group Title
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    Yes, I believe the OP means raised to the power of x. Not linear in x.

    • one year ago
  6. Hashir Group Title
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    |dw:1343887451360:dw|

    • one year ago
  7. Hashir Group Title
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    if its a raised power then may be its decay

    • one year ago
  8. ParthKohli Group Title
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    @Hashir The question is\[5 \times 0.5^x\]

    • one year ago
  9. qpHalcy0n Group Title
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    Well, if its raised to x, its DEFINITELY decay, not maybe.

    • one year ago
  10. greener6 Group Title
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    so if the number in the parentheses is lower then 1 its decay

    • one year ago
  11. ParthKohli Group Title
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    When people copy and paste questions, they don't type out ^ before powers.

    • one year ago
  12. UnkleRhaukus Group Title
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    \[y(x) = 5(0.5)^x\] lets try some points \[y(0) = 5(0.5)^0=5\] \[y(1) = 5(0.5)^1=5\times0.5=2.5\] \[y(2) = 5(0.5)^2=5\times0.25=1.25\] as x goes up y decreases , decay

    • one year ago
  13. ParthKohli Group Title
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    Yes @greener6

    • one year ago
  14. UnkleRhaukus Group Title
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    |dw:1343887585554:dw|

    • one year ago
  15. UnkleRhaukus Group Title
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    |dw:1343887677903:dw|

    • one year ago
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