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Hint:
\(\tan x(\tan x - 1) = 0\)

2nd Hint:
\(\tan x = 0\)
\(\tan x - 1 = 0\)

\[\frac{\sin^2(x)}{\cos^2(x)} - \frac{\sin(x)}{\cos(x)} = 0\]
=
what makes sin(x) = 0?

Third Hint:
\( x = \tan^{-1}(0)\)
\(x = \tan^{-1}(1)\)

what ever makes sin(x) 0 makes tan(x) = 0

No giving of answers @muhammad9t5

hi let tanx=y then solve it by factorizing or quadratic equation.

@IloveCharlie did you get me?

its better to solve it yourself...

@IloveCharlie do you understand?

So 0 degree into radians= 0. 45 degree into radians= pi/4

|dw:1343892306689:dw|

question plee

@IloveCharlie yes.

this is the unit circle look at the coordinates for the radians

and then read what I said

remember
when sin(x) = 1
sin(x)^(2) = 1^(2) = 1

@IloveCharlie whats up?

pi/4?

That's what I got from reading the chart you provided

But pi/4 is in all options. How do I know which one it is

thre are two answer 0 and pi/4 for all solutions
{0}U{pi/4}
{pi/4} answer.

So c. Thank you so much! I appreciate everyones help

i was just waiting for it!!!!!!!!! hahahaha Thanks.