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Yahoo! Group Title

A small block of mass 0.1kg lies on a fixed inclined plane PQ which makes an angle x with horizontal.A horizontal force of 1N on the block through its center of mass as shown The block remains stationary if x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q

  • one year ago
  • one year ago

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  1. Yahoo! Group Title
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    |dw:1343893542262:dw|

    • one year ago
  2. best.shakir Group Title
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    x > 45 and friction acts towards Q

    • one year ago
  3. best.shakir Group Title
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    i will explain

    • one year ago
  4. thushananth01 Group Title
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    |dw:1343894068439:dw|

    • one year ago
  5. Yahoo! Group Title
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    @thushananth01 Plzz Procede

    • one year ago
  6. thushananth01 Group Title
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    give me a min

    • one year ago
  7. Yahoo! Group Title
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    OK

    • one year ago
  8. celos Group Title
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    x = \[45^{o}\]

    • one year ago
  9. Yahoo! Group Title
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    hw

    • one year ago
  10. celos Group Title
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    |dw:1343894414685:dw| mgsinx=1Ncosx g=10m/s

    • one year ago
  11. Yahoo! Group Title
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    ok.......... This is a multiple choice correct answer there is one more option which is correct..

    • one year ago
  12. Ishaan94 Group Title
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    x=45

    • one year ago
  13. Ishaan94 Group Title
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    |dw:1343894824349:dw|

    • one year ago
  14. Ishaan94 Group Title
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    friction?

    • one year ago
  15. Yahoo! Group Title
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    x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q

    • one year ago
  16. Ishaan94 Group Title
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    If I take g=10. sinx = cosx only when x=45.

    • one year ago
  17. Yahoo! Group Title
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    ok.....1 st opt ion is correct .......i1 more we want

    • one year ago
  18. Ishaan94 Group Title
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    If g=9.8. sinx < cos x. So to make it stationary I would need friction towards P.

    • one year ago
  19. Ishaan94 Group Title
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    okay. so g must be 10. other option should be the third one. if x>45. sinx>cosx. and for block to be stationary we need friction towards Q.

    • one year ago
  20. Yahoo! Group Title
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    @Ishaan94 in the question it is said that g =10m/s^2 i forgot to mention

    • one year ago
  21. celos Group Title
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    if g =10 m/s^{2} then there is no friction because it arises when there is any tendency of motion. but at x =\[45^{o}\] the net force is zero.

    • one year ago
  22. Yahoo! Group Title
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    thxxx

    • one year ago
  23. ghazi Group Title
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    m*g*sin(x)= 1* cos (x)substituting the value of m and g will give x= 45

    • one year ago
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