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A small block of mass 0.1kg lies on a fixed inclined plane PQ which makes an angle x with horizontal.A horizontal force of 1N on the block through its center of mass as shown The block remains stationary if
x = 45
x > 45 and friction acts towards p
x > 45 and friction acts towards Q
x < 45 and friction acts towards Q
 2 years ago
 2 years ago
Yahoo! Group Title
A small block of mass 0.1kg lies on a fixed inclined plane PQ which makes an angle x with horizontal.A horizontal force of 1N on the block through its center of mass as shown The block remains stationary if x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q
 2 years ago
 2 years ago

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Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
dw:1343893542262:dw
 2 years ago

best.shakir Group TitleBest ResponseYou've already chosen the best response.0
x > 45 and friction acts towards Q
 2 years ago

best.shakir Group TitleBest ResponseYou've already chosen the best response.0
i will explain
 2 years ago

thushananth01 Group TitleBest ResponseYou've already chosen the best response.0
dw:1343894068439:dw
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@thushananth01 Plzz Procede
 2 years ago

thushananth01 Group TitleBest ResponseYou've already chosen the best response.0
give me a min
 2 years ago

celos Group TitleBest ResponseYou've already chosen the best response.0
x = \[45^{o}\]
 2 years ago

celos Group TitleBest ResponseYou've already chosen the best response.0
dw:1343894414685:dw mgsinx=1Ncosx g=10m/s
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
ok.......... This is a multiple choice correct answer there is one more option which is correct..
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
dw:1343894824349:dw
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
If I take g=10. sinx = cosx only when x=45.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
ok.....1 st opt ion is correct .......i1 more we want
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
If g=9.8. sinx < cos x. So to make it stationary I would need friction towards P.
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
okay. so g must be 10. other option should be the third one. if x>45. sinx>cosx. and for block to be stationary we need friction towards Q.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@Ishaan94 in the question it is said that g =10m/s^2 i forgot to mention
 2 years ago

celos Group TitleBest ResponseYou've already chosen the best response.0
if g =10 m/s^{2} then there is no friction because it arises when there is any tendency of motion. but at x =\[45^{o}\] the net force is zero.
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.0
m*g*sin(x)= 1* cos (x)substituting the value of m and g will give x= 45
 2 years ago
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