## Yahoo! 3 years ago A small block of mass 0.1kg lies on a fixed inclined plane PQ which makes an angle x with horizontal.A horizontal force of 1N on the block through its center of mass as shown The block remains stationary if x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q

1. Yahoo!

|dw:1343893542262:dw|

2. best.shakir

x > 45 and friction acts towards Q

3. best.shakir

i will explain

4. thushananth01

|dw:1343894068439:dw|

5. Yahoo!

@thushananth01 Plzz Procede

6. thushananth01

give me a min

7. Yahoo!

OK

8. celos

x = \[45^{o}\]

9. Yahoo!

hw

10. celos

|dw:1343894414685:dw| mgsinx=1Ncosx g=10m/s

11. Yahoo!

ok.......... This is a multiple choice correct answer there is one more option which is correct..

12. Ishaan94

x=45

13. Ishaan94

|dw:1343894824349:dw|

14. Ishaan94

friction?

15. Yahoo!

x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q

16. Ishaan94

If I take g=10. sinx = cosx only when x=45.

17. Yahoo!

ok.....1 st opt ion is correct .......i1 more we want

18. Ishaan94

If g=9.8. sinx < cos x. So to make it stationary I would need friction towards P.

19. Ishaan94

okay. so g must be 10. other option should be the third one. if x>45. sinx>cosx. and for block to be stationary we need friction towards Q.

20. Yahoo!

@Ishaan94 in the question it is said that g =10m/s^2 i forgot to mention

21. celos

if g =10 m/s^{2} then there is no friction because it arises when there is any tendency of motion. but at x =\[45^{o}\] the net force is zero.

22. Yahoo!

thxxx

23. ghazi

m*g*sin(x)= 1* cos (x)substituting the value of m and g will give x= 45