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A small block of mass 0.1kg lies on a fixed inclined plane PQ which makes an angle x with horizontal.A horizontal force of 1N on the block through its center of mass as shown The block remains stationary if
x = 45
x > 45 and friction acts towards p
x > 45 and friction acts towards Q
x < 45 and friction acts towards Q
 one year ago
 one year ago
Yahoo! Group Title
A small block of mass 0.1kg lies on a fixed inclined plane PQ which makes an angle x with horizontal.A horizontal force of 1N on the block through its center of mass as shown The block remains stationary if x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q
 one year ago
 one year ago

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Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
dw:1343893542262:dw
 one year ago

best.shakir Group TitleBest ResponseYou've already chosen the best response.0
x > 45 and friction acts towards Q
 one year ago

best.shakir Group TitleBest ResponseYou've already chosen the best response.0
i will explain
 one year ago

thushananth01 Group TitleBest ResponseYou've already chosen the best response.0
dw:1343894068439:dw
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@thushananth01 Plzz Procede
 one year ago

thushananth01 Group TitleBest ResponseYou've already chosen the best response.0
give me a min
 one year ago

celos Group TitleBest ResponseYou've already chosen the best response.0
x = \[45^{o}\]
 one year ago

celos Group TitleBest ResponseYou've already chosen the best response.0
dw:1343894414685:dw mgsinx=1Ncosx g=10m/s
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
ok.......... This is a multiple choice correct answer there is one more option which is correct..
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
dw:1343894824349:dw
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
friction?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
If I take g=10. sinx = cosx only when x=45.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
ok.....1 st opt ion is correct .......i1 more we want
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
If g=9.8. sinx < cos x. So to make it stationary I would need friction towards P.
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.2
okay. so g must be 10. other option should be the third one. if x>45. sinx>cosx. and for block to be stationary we need friction towards Q.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@Ishaan94 in the question it is said that g =10m/s^2 i forgot to mention
 one year ago

celos Group TitleBest ResponseYou've already chosen the best response.0
if g =10 m/s^{2} then there is no friction because it arises when there is any tendency of motion. but at x =\[45^{o}\] the net force is zero.
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.0
m*g*sin(x)= 1* cos (x)substituting the value of m and g will give x= 45
 one year ago
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