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 2 years ago
A small block of mass 0.1kg lies on a fixed inclined plane PQ which makes an angle x with horizontal.A horizontal force of 1N on the block through its center of mass as shown The block remains stationary if
x = 45
x > 45 and friction acts towards p
x > 45 and friction acts towards Q
x < 45 and friction acts towards Q
 2 years ago
A small block of mass 0.1kg lies on a fixed inclined plane PQ which makes an angle x with horizontal.A horizontal force of 1N on the block through its center of mass as shown The block remains stationary if x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q

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best.shakir
 2 years ago
Best ResponseYou've already chosen the best response.0x > 45 and friction acts towards Q

thushananth01
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1343894068439:dw

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0@thushananth01 Plzz Procede

celos
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1343894414685:dw mgsinx=1Ncosx g=10m/s

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0ok.......... This is a multiple choice correct answer there is one more option which is correct..

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0x = 45 x > 45 and friction acts towards p x > 45 and friction acts towards Q x < 45 and friction acts towards Q

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.2If I take g=10. sinx = cosx only when x=45.

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0ok.....1 st opt ion is correct .......i1 more we want

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.2If g=9.8. sinx < cos x. So to make it stationary I would need friction towards P.

Ishaan94
 2 years ago
Best ResponseYou've already chosen the best response.2okay. so g must be 10. other option should be the third one. if x>45. sinx>cosx. and for block to be stationary we need friction towards Q.

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0@Ishaan94 in the question it is said that g =10m/s^2 i forgot to mention

celos
 2 years ago
Best ResponseYou've already chosen the best response.0if g =10 m/s^{2} then there is no friction because it arises when there is any tendency of motion. but at x =\[45^{o}\] the net force is zero.

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.0m*g*sin(x)= 1* cos (x)substituting the value of m and g will give x= 45
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