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The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?

  • 2 years ago
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  1. zbay Group Title
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    do you got any formulas to work with?

    • 2 years ago
  2. Yahoo! Group Title
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    No idea

    • 2 years ago
  3. zbay Group Title
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    yea i'm sorry i don't think i will be able to help with this one

    • 2 years ago
  4. Yahoo! Group Title
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    Can u call some one else

    • 2 years ago
  5. Ishaan94 Group Title
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    .587?

    • 2 years ago
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    yes u r correct @Ishaan94

    • 2 years ago
  7. Yahoo! Group Title
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    @Ishaan94 hw do u get it

    • 2 years ago
  8. Ishaan94 Group Title
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    Vapor density of dissociation vapor = 127. Let x be the degree of dissociation. 80/120 = 1/(1+x) => x = .587 I hope you can get the equation and number moles at equilibrium.

    • 2 years ago
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