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Yahoo!

  • 3 years ago

The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?

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  1. zbay
    • 3 years ago
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    do you got any formulas to work with?

  2. Yahoo!
    • 3 years ago
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    No idea

  3. zbay
    • 3 years ago
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    yea i'm sorry i don't think i will be able to help with this one

  4. Yahoo!
    • 3 years ago
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    Can u call some one else

  5. Ishaan94
    • 3 years ago
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    .587?

  6. Yahoo!
    • 3 years ago
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    yes u r correct @Ishaan94

  7. Yahoo!
    • 3 years ago
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    @Ishaan94 hw do u get it

  8. Ishaan94
    • 3 years ago
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    Vapor density of dissociation vapor = 127. Let x be the degree of dissociation. 80/120 = 1/(1+x) => x = .587 I hope you can get the equation and number moles at equilibrium.

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