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The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?
 one year ago
 one year ago
Yahoo! Group Title
The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?
 one year ago
 one year ago

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zbay Group TitleBest ResponseYou've already chosen the best response.0
do you got any formulas to work with?
 one year ago

zbay Group TitleBest ResponseYou've already chosen the best response.0
yea i'm sorry i don't think i will be able to help with this one
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Can u call some one else
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
yes u r correct @Ishaan94
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@Ishaan94 hw do u get it
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
Vapor density of dissociation vapor = 127. Let x be the degree of dissociation. 80/120 = 1/(1+x) => x = .587 I hope you can get the equation and number moles at equilibrium.
 one year ago
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