anonymous
  • anonymous
The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
do you got any formulas to work with?
anonymous
  • anonymous
No idea
anonymous
  • anonymous
yea i'm sorry i don't think i will be able to help with this one

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anonymous
  • anonymous
Can u call some one else
anonymous
  • anonymous
.587?
anonymous
  • anonymous
yes u r correct @Ishaan94
anonymous
  • anonymous
@Ishaan94 hw do u get it
anonymous
  • anonymous
Vapor density of dissociation vapor = 127. Let x be the degree of dissociation. 80/120 = 1/(1+x) => x = .587 I hope you can get the equation and number moles at equilibrium.

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