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The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?
do you got any formulas to work with?
yea i'm sorry i don't think i will be able to help with this one
Can u call some one else
yes u r correct @Ishaan94
@Ishaan94 hw do u get it
Vapor density of dissociation vapor = 127. Let x be the degree of dissociation. 80/120 = 1/(1+x) => x = .587 I hope you can get the equation and number moles at equilibrium.