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The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?
 one year ago
 one year ago
The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?
 one year ago
 one year ago

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zbayBest ResponseYou've already chosen the best response.0
do you got any formulas to work with?
 one year ago

zbayBest ResponseYou've already chosen the best response.0
yea i'm sorry i don't think i will be able to help with this one
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Can u call some one else
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
yes u r correct @Ishaan94
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
@Ishaan94 hw do u get it
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
Vapor density of dissociation vapor = 127. Let x be the degree of dissociation. 80/120 = 1/(1+x) => x = .587 I hope you can get the equation and number moles at equilibrium.
 one year ago
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