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anonymous
 4 years ago
The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?
anonymous
 4 years ago
The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you got any formulas to work with?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea i'm sorry i don't think i will be able to help with this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can u call some one else

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes u r correct @Ishaan94

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Ishaan94 hw do u get it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Vapor density of dissociation vapor = 127. Let x be the degree of dissociation. 80/120 = 1/(1+x) => x = .587 I hope you can get the equation and number moles at equilibrium.
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