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koli123able

  • 2 years ago

Factorize x^4-12x^2-64=0

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  1. mathslover
    • 2 years ago
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    64 = 8^2 right?

  2. koli123able
    • 2 years ago
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    middle term breaking

  3. koli123able
    • 2 years ago
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    breaking 12x^2

  4. ayushprasad
    • 2 years ago
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    (x^2-16)(x^2+4)

  5. mathslover
    • 2 years ago
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    ok .. : \[\large{x^4+4x^2-16x^2-64=0}\] right?

  6. koli123able
    • 2 years ago
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    absolutely right

  7. koli123able
    • 2 years ago
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    then factorize it again

  8. mathslover
    • 2 years ago
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    ok now .. \[\large{x^2(x^2+4)-16x^2-64=0}\] right?

  9. koli123able
    • 2 years ago
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    (x^2-16)(x^2+4)

  10. ayushprasad
    • 2 years ago
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    (x^2-16)(x^2+4)= (x-4)(x+4)(x^2+4)

  11. mathslover
    • 2 years ago
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    right : \[\large{(a^2-b^2)=(a+b)(a-b)}\]

  12. mathslover
    • 2 years ago
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    \[\large{x^2-4^2=(x+4)(x-4)}\]

  13. koli123able
    • 2 years ago
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    x=+4,-4

  14. koli123able
    • 2 years ago
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    the formula is right but i need to solve this without formula

  15. hal_stirrup
    • 2 years ago
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    hoe do you know that????? x=+4,-4

  16. koli123able
    • 2 years ago
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    x2=16 squaring x=+4,-4

  17. koli123able
    • 2 years ago
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    then after that the hard part

  18. koli123able
    • 2 years ago
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    using x+4=0

  19. koli123able
    • 2 years ago
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    sorry x2+4=0

  20. koli123able
    • 2 years ago
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    x^2=-4 squaring x=+2i,-2i

  21. hal_stirrup
    • 2 years ago
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    you mean x^2+4=0

  22. koli123able
    • 2 years ago
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    yeah

  23. koli123able
    • 2 years ago
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    its done ok fine thanks for help every body

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spraguer (Moderator)
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