anonymous
  • anonymous
Factorize x^4-12x^2-64=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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mathslover
  • mathslover
64 = 8^2 right?
anonymous
  • anonymous
middle term breaking
anonymous
  • anonymous
breaking 12x^2

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anonymous
  • anonymous
(x^2-16)(x^2+4)
mathslover
  • mathslover
ok .. : \[\large{x^4+4x^2-16x^2-64=0}\] right?
anonymous
  • anonymous
absolutely right
anonymous
  • anonymous
then factorize it again
mathslover
  • mathslover
ok now .. \[\large{x^2(x^2+4)-16x^2-64=0}\] right?
anonymous
  • anonymous
(x^2-16)(x^2+4)
anonymous
  • anonymous
(x^2-16)(x^2+4)= (x-4)(x+4)(x^2+4)
mathslover
  • mathslover
right : \[\large{(a^2-b^2)=(a+b)(a-b)}\]
mathslover
  • mathslover
\[\large{x^2-4^2=(x+4)(x-4)}\]
anonymous
  • anonymous
x=+4,-4
anonymous
  • anonymous
the formula is right but i need to solve this without formula
anonymous
  • anonymous
hoe do you know that????? x=+4,-4
anonymous
  • anonymous
x2=16 squaring x=+4,-4
anonymous
  • anonymous
then after that the hard part
anonymous
  • anonymous
using x+4=0
anonymous
  • anonymous
sorry x2+4=0
anonymous
  • anonymous
x^2=-4 squaring x=+2i,-2i
anonymous
  • anonymous
you mean x^2+4=0
anonymous
  • anonymous
yeah
anonymous
  • anonymous
its done ok fine thanks for help every body

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