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Factorize x^4-12x^2-64=0

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64 = 8^2 right?
middle term breaking
breaking 12x^2

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Other answers:

ok .. : \[\large{x^4+4x^2-16x^2-64=0}\] right?
absolutely right
then factorize it again
ok now .. \[\large{x^2(x^2+4)-16x^2-64=0}\] right?
(x^2-16)(x^2+4)= (x-4)(x+4)(x^2+4)
right : \[\large{(a^2-b^2)=(a+b)(a-b)}\]
the formula is right but i need to solve this without formula
hoe do you know that????? x=+4,-4
x2=16 squaring x=+4,-4
then after that the hard part
using x+4=0
sorry x2+4=0
x^2=-4 squaring x=+2i,-2i
you mean x^2+4=0
its done ok fine thanks for help every body

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