Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
hiralpatel121
Group Title
A solid sphere rolls down a hill of height 60 m. What is the velocity of the ball when it reaches the bottom?
 2 years ago
 2 years ago
hiralpatel121 Group Title
A solid sphere rolls down a hill of height 60 m. What is the velocity of the ball when it reaches the bottom?
 2 years ago
 2 years ago

This Question is Closed

JopHP Group TitleBest ResponseYou've already chosen the best response.0
since it rolls down from a height so it's initial velocity U=0 & it's Acc.=the gravititional Acc=9.8 m/sec^2 therefore by applying the law of motion V^2=U^2+2GS therefore: V^2=0+2(9.8)(60)=1176 m^2/sec^2 So. V=34.29 m/sec
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.0
@JopHP what you've mentioned here is case of free fall when angle of inclination is 90 degrees in this case ball is rolling down the hill so velocity will be different @hiralpatel can you mention the angle of inclination...but there is one more question angle of inclination will keep changing...
 2 years ago

JopHP Group TitleBest ResponseYou've already chosen the best response.0
i know that @ghazi but those are the permitted givens
 2 years ago

rkphysics Group TitleBest ResponseYou've already chosen the best response.0
\[\[V_{final}^2= 2[g.\cos \theta ]*[h/\cos \theta]\] for any inclination theta, so final velocity will be same if it is a steep hill or a nearly flat one!!! assuming the ball started from rest and neglecting friction
 2 years ago

CarlosGP Group TitleBest ResponseYou've already chosen the best response.0
Here goes the solution. Potential Energy turns into Kinetic and Rotation Energy
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.