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AravindG
 4 years ago
Is this identity valid ?
AravindG
 4 years ago
Is this identity valid ?

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AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0\[\large \tan^{1}x+\tan^{1}y+\tan^{1}z=\tan^{1}\frac{x+y+zxyz}{1xyyzzx}\]

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus , @.Sam. , @Callisto

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol.....im wrong...nothing.......lets think again

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0@amistre64 , @experimentX

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1no that's the right trick ... test for few arbitrary values.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1that's how i validate things ... before doing it if it looks ugly.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0i jst got to this eqn by myseslf ... so i dont knw ifthis can be generalised for all x,y,q

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0i didnt see such an identituy in any textbook, i only saw tan1 x+tan1 y

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0can anyone tell me if this is valid for all x,y ,z?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is this correct?\[\tan^{1}x +\tan^{1}y=\tan^{1}\frac{x+y}{1xy} \]

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0thats why i thought of an analogous for 3x :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is this correct?\[\tan^{1}x +\tan^{1}y+\tan^{1}z=\tan^{1}\frac{x+y}{1xy}+\tan^{1}z\\=\tan^{1}\frac{z+\frac{x+y}{1xy}}{1z\frac{x+y}{1xy}}=\tan^{1}\frac{x+y+zxyz}{1xyxzzy}\] so its valid

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol.....ignore' is this correct?'

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1lol .. that's correct!!

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0:P thx a lot!!!!!!!!!!!!!!!!!!!111

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just remember that it is not valid for x belonging to R due to the domain range conditions you may need to add subtract pi. Otherwise its fine.
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