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AravindG Group TitleBest ResponseYou've already chosen the best response.0
\[\large \tan^{1}x+\tan^{1}y+\tan^{1}z=\tan^{1}\frac{x+y+zxyz}{1xyyzzx}\]
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus , @.Sam. , @Callisto
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.6
let x=y=z=1
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.6
lol.....im wrong...nothing.......lets think again
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
@amistre64 , @experimentX
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
no that's the right trick ... test for few arbitrary values.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
that's how i validate things ... before doing it if it looks ugly.
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i jst got to this eqn by myseslf ... so i dont knw ifthis can be generalised for all x,y,q
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i didnt see such an identituy in any textbook, i only saw tan1 x+tan1 y
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
can anyone tell me if this is valid for all x,y ,z?
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.6
is this correct?\[\tan^{1}x +\tan^{1}y=\tan^{1}\frac{x+y}{1xy} \]
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
thats why i thought of an analogous for 3x :P
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i mean x,y ,z
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.6
is this correct?\[\tan^{1}x +\tan^{1}y+\tan^{1}z=\tan^{1}\frac{x+y}{1xy}+\tan^{1}z\\=\tan^{1}\frac{z+\frac{x+y}{1xy}}{1z\frac{x+y}{1xy}}=\tan^{1}\frac{x+y+zxyz}{1xyxzzy}\] so its valid
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.6
lol.....ignore' is this correct?'
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
lol .. that's correct!!
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
:P thx a lot!!!!!!!!!!!!!!!!!!!111
 2 years ago

siddhantsharan Group TitleBest ResponseYou've already chosen the best response.0
Just remember that it is not valid for x belonging to R due to the domain range conditions you may need to add subtract pi. Otherwise its fine.
 2 years ago

siddhantsharan Group TitleBest ResponseYou've already chosen the best response.0
@AravindG
 one year ago
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