anonymous
  • anonymous
What is the solution of log 2x – 3^125 = 3 ? x = 1 over 3 x = 1 x = 7 over 3 x = 4
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
log basex a = b implies x^a = b
anonymous
  • anonymous
i dont understand
anonymous
  • anonymous
Is this correct? \[\Large \log (2x-3^{125}) = 3\]

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anonymous
  • anonymous
nah the base is 2x - 3
anonymous
  • anonymous
so confuse >.<
anonymous
  • anonymous
@telltoamit Only @gioanny39x can say that for sure. Gio, you need to confirm if I have the equation correct or not. Also, your formula is wrong. \[\Large log_B(X) = Y\] is the same as \[\Large X = B^{Y}\] Example: \[\Large log_10(1000) = 3\] B = 10 X = 1000 Y = 3 Using the 2nd form of the equation: \[\Large X = B^{Y}\] \[\Large 1000 = 10^{3}\]
ash2326
  • ash2326
\[\log_{2x-3} 125=3\] Is this your question @gioanny39x ?
anonymous
  • anonymous
only this gives the answer in options lol
anonymous
  • anonymous
|dw:1343929733059:dw|
anonymous
  • anonymous
Ok, so: B = 2D-3 (easier to use D to not confuse with X) X = 125 Y = 3 \[\Large X = B^{Y}\] \[\Large 125 = (2D-3)^{3}\] Solve for D. Hint: 125 is the cube of a single digit number.
anonymous
  • anonymous
(2d-3)(2d-3)(2d-3) 4d^2-6d-6d+9 4d^2-12d+9(2d-3) 8d^3-12d^2 -24d^2+36d 28d-27 125=8d^3=36d^2+64d+27?
anonymous
  • anonymous
anonymous
  • anonymous
You're creating too much work for yourself. What is the cube root of 5? Hint: \[\Large X^{3} = (15Y+5)^{3}\] \[\Large X = (15Y+5)\] If you have two items that when cubed equal each other, the items equal each other.

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