OSUxBucks15
  • OSUxBucks15
What image is the translation of ABC given by the translation rule ( x,y ) ( x – 2, y – 2)?
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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OSUxBucks15
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The last four wer answer choices
anonymous
  • anonymous
The last one is the answer. ( x,y ) ( x – 2, y – 2) means the original x value is subtracted 2 units and the y value is subtracted 2 units so on the x axis, the object is moving left 2 units because the x value of each point is being reduced. On the y axis, the object is moving down 2 units.
anonymous
  • anonymous
Subtracting a positive value from x moves the figure left. Subtracting positive value from y moves it down. The opposite of each is true when a positive value is added instead of subtracted.
anonymous
  • anonymous
Sometimes, for questions where I don't know the way to soilve or simply forget how to solve, I just test out a simpler version but same concept so I take any random point like (1,1) and apply the transformation rule above then see how it moves on a graph. I would get (-1,-1) and can tell how the rule exactly affects the original. Sometimes, this usage of a simpler problem while maintaining the same concept can greatly help one make an educated guess. It's proven to be very helpful for SATs where sometimes you just have to make an educated guess based on what you do know.
OSUxBucks15
  • OSUxBucks15
thanks
anonymous
  • anonymous
No problem

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