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j814wong

  • 2 years ago

Let A,B, and C be three points in a plane such that AB:BC = 3:5. Which of the following can be the ratio of AB:AC? I. 1:2 II. 1:3 III. 3:8 A. I only B. II only C. III only D. I and III only E. I, II, and III

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  1. amistre64
    • 2 years ago
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    might help to draw it out

  2. amistre64
    • 2 years ago
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    |dw:1343938402235:dw|

  3. amistre64
    • 2 years ago
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    write the ratios as fractions so see if any of them are equal to each other as well

  4. j814wong
    • 2 years ago
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    Oh I see. So 3:8 works. And 1:2 also works if I draw it this way.|dw:1343939315480:dw| Thanks. I guess where I was thrown off was that the question said three points on a plane instead of line.

  5. amistre64
    • 2 years ago
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    ab:ac 3 : 2 3/2 not equal to 1/2 tho

  6. amistre64
    • 2 years ago
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    but, what if they form a triangle instead of a line?

  7. amistre64
    • 2 years ago
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    |dw:1343939637228:dw|

  8. j814wong
    • 2 years ago
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    If that happens, how should I go about it?

  9. amistre64
    • 2 years ago
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    a triangle has the property that the sum of 2 sides is greater than the remaining side

  10. amistre64
    • 2 years ago
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    |dw:1344178277031:dw| AC would be bounded between 2 and 8

  11. amistre64
    • 2 years ago
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    therefore our ratio is bounded between: 3/2 and 3/8 3/2, 1 : .666 3/3, 1 : 1 3/4, 1 : 1.333 3/5, 1 : 1.666 3/6, 1 : 2 3/7, 1 : 2.333 3/8, 1 : 2. 666

  12. amistre64
    • 2 years ago
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    or we could just take the 3 options and get them to the 3 : n ratio .... 3:6 3:9 3:8 since 3:9 is out of bounds, and the other 2 are in bounds, it would appear to me to be I and III

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