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No.

okay .. :(

Harsh. @lgbasallote

haha lol

So help her already. I dont know what that is, lol. Can you atleast try? @lgbasallote

i have no idea

yeah yeah , at least try if u can .. :)

I'm not sure what you mean, you want to derive the three series expansions above?

@greysica do I understand that you just want to see how the above statements are derived?

I have to find the way how it works as a function based on mac laurin polinom

I can derive the mcLauren series from the function, but that doesn't sound like what you want.

is that for A ?

ya :)

x=0 ?

not not x=0

|dw:1344008695732:dw|

what is \(f^{(0)}(x)\) when \(f(x)=a^x\)
that is, what is the 0th derivative?

devivative of 0 = 1 ?

I dont understand about derivative actually .. is that ax^x-1 ?

you say you don't know how to take the derivative of a function?

ya , I dont know how , I really confuse about this subject

f(0) ?

yes, and what is f(0) in this case?

so f(0)=a^x ?

f(0)=a^0

f(0)=1 ?

or f(0)= a ?

f(n)(0)=1
---------1 ??
0!

right
should have written f^(0)(0) but still, that's right
so what does all that simplify to?

1/0 * 1 ?

\[f^{(0)}(0)=f(0)=a^0=1\] and \[x^0=1\]true, but\[0!\neq0\]

\[0!=1\]by definition

so try again, what does it simplify too?

\[T_0(a^x)={f^{(0)}(0)\over 0!}x^0={a^0\over0!}x^0=?\]

1/1 * 1= 1

correct, that is the first term :)

(f^1)(0)
----------x^1
1!

and what is \(f^{(1)}(0)\) for \(f(x)=a^x\) ?

0/1 * 1 ?

*I think you have...

n^th ? what does mean ?

so 1^1
--------1 ??
1!

1! = 2 right ? 1! means 1+1*1 = 2 ? like that ?

or 1 ! = 1*1 = 1 ?

oh ..

i dunno :(

ax^x-1 ?

f (x) + f '(x) ?

f^0 (x) ?

ughh .. okay .. thanks ,,,

what is \[\frac d{dx}(a^x)\]?

a^x ln(a)

yes

what is the meaning of In ?

I'm so desperate and shame about this .. thank u for trying help me