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hal_stirrup
 3 years ago
Finding max and min.......
F(x)=2x^330x^2+126x+59
explain the steps plz... thanks
hal_stirrup
 3 years ago
Finding max and min....... F(x)=2x^330x^2+126x+59 explain the steps plz... thanks

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Stacey
 3 years ago
Best ResponseYou've already chosen the best response.01) Take the derivative first, then set the derivative equal to zero and solve for x. 2) Check the slope on each side of the values found to see if the value is a max or min.

Jow
 3 years ago
Best ResponseYou've already chosen the best response.0Well, take the derivative of F(x). Then, solve for x. You will find a value, which can be a max or a min. TO know if it' s a max or a min, you have to know the concavity. The derivatives are useful in this case because there is a point which the slope of the derivative is 0. These are the points of interest.

hal_stirrup
 3 years ago
Best ResponseYou've already chosen the best response.0take the 2nd derivative and see if F''(x) >0 or F''(x) <0
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