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katiebugg

  • 2 years ago

help?!?!?!?! find the variables not given a1 = 10, r = 3, n = 5

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  1. jim_thompson5910
    • 2 years ago
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    This looks like a geometric sequence

  2. katiebugg
    • 2 years ago
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    it is

  3. jim_thompson5910
    • 2 years ago
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    an = a1*r^(n-1) is the general formula

  4. jim_thompson5910
    • 2 years ago
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    In this case, a1 = 10 and r = 3, so an = 10*3^(n-1)

  5. jim_thompson5910
    • 2 years ago
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    the nth term, an, in this case is the 5th term since n = 5 so a5 = 10*3^(5-1)

  6. jim_thompson5910
    • 2 years ago
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    or an = 10*3^(5-1) when n = 5

  7. subjectgeek
    • 2 years ago
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    High school math or what?

  8. sauravshakya
    • 2 years ago
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    so,|dw:1343971838905:dw|

  9. jim_thompson5910
    • 2 years ago
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    does that make sense?

  10. katiebugg
    • 2 years ago
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    .... no

  11. jim_thompson5910
    • 2 years ago
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    I'm assuming you want to find an right?

  12. jim_thompson5910
    • 2 years ago
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    The term \(\Large a_{n}\)

  13. katiebugg
    • 2 years ago
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    yess its the one missing

  14. jim_thompson5910
    • 2 years ago
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    \[\Large a_{n} = a_{1}r^{n-1}\] \[\Large a_{n} = 10*3^{n-1}\] \[\Large a_{n} = 10*3^{5-1}\] I'll let you finish

  15. katiebugg
    • 2 years ago
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    lol thanks

  16. jim_thompson5910
    • 2 years ago
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    you're welcome, tell me what you get

  17. katiebugg
    • 2 years ago
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    810???

  18. jim_thompson5910
    • 2 years ago
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    you are correct

  19. katiebugg
    • 2 years ago
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    lol yay!!!!!! soo i just do that when looking for then An then lol

  20. jim_thompson5910
    • 2 years ago
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    exactly

  21. jim_thompson5910
    • 2 years ago
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    \(\Large a_{n}\) is the nth term. So in this case, when n = 5, \(\Large a_{n}\) is the 5th term Another way to say this \(\Large a_{5}\)

  22. katiebugg
    • 2 years ago
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    lol ok

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