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katiebugg Group Title

I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected?

  • one year ago
  • one year ago

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  1. alexwee123 Group Title
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    |dw:1343977571380:dw|

    • one year ago
  2. katiebugg Group Title
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    i have no idea

    • one year ago
  3. alexwee123 Group Title
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    this might help :) |dw:1343977665844:dw|

    • one year ago
  4. katiebugg Group Title
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    i think so how would i aply that

    • one year ago
  5. alexwee123 Group Title
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    for your question n=15 and r=6 so |dw:1343977816649:dw| now can you solve it?

    • one year ago
  6. katiebugg Group Title
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    why the !

    • one year ago
  7. alexwee123 Group Title
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    oh it means factorial take "5!" for example 5!=5x4x3x2x1

    • one year ago
  8. alexwee123 Group Title
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    so apply this to the current problem :o

    • one year ago
  9. katiebugg Group Title
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    soo whats 15 c x 10

    • one year ago
  10. alexwee123 Group Title
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    what do you think it is?

    • one year ago
  11. katiebugg Group Title
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    idk am i multiplying it by the 15

    • one year ago
  12. alexwee123 Group Title
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    answer is 5005...

    • one year ago
  13. alexwee123 Group Title
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    but do you get how i got this?

    • one year ago
  14. katiebugg Group Title
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    i want to say yess but i cant

    • one year ago
  15. alexwee123 Group Title
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    ok look :o \[15!=15\times14\times13\times12\times11\times......\times1 \] and\[9!=\times8\times7\times6\times5\times...1 and 6!=6\times5\times4\times3\times2\times1\] so if you sub this in, we can easily simplify the equation \[(15\times14\times13\times12\times11\times10\times9!)\div(6!(9!))\] you can cancel out the 9! and be left w/\[(15\times14\times13\times12\times11\times10)\div(6!)\] then just simplify by using intuition

    • one year ago
  16. katiebugg Group Title
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    ohhh ok lol

    • one year ago
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