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katiebugg

  • 3 years ago

I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected?

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  1. alexwee123
    • 3 years ago
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    |dw:1343977571380:dw|

  2. katiebugg
    • 3 years ago
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    i have no idea

  3. alexwee123
    • 3 years ago
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    this might help :) |dw:1343977665844:dw|

  4. katiebugg
    • 3 years ago
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    i think so how would i aply that

  5. alexwee123
    • 3 years ago
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    for your question n=15 and r=6 so |dw:1343977816649:dw| now can you solve it?

  6. katiebugg
    • 3 years ago
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    why the !

  7. alexwee123
    • 3 years ago
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    oh it means factorial take "5!" for example 5!=5x4x3x2x1

  8. alexwee123
    • 3 years ago
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    so apply this to the current problem :o

  9. katiebugg
    • 3 years ago
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    soo whats 15 c x 10

  10. alexwee123
    • 3 years ago
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    what do you think it is?

  11. katiebugg
    • 3 years ago
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    idk am i multiplying it by the 15

  12. alexwee123
    • 3 years ago
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    answer is 5005...

  13. alexwee123
    • 3 years ago
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    but do you get how i got this?

  14. katiebugg
    • 3 years ago
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    i want to say yess but i cant

  15. alexwee123
    • 3 years ago
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    ok look :o \[15!=15\times14\times13\times12\times11\times......\times1 \] and\[9!=\times8\times7\times6\times5\times...1 and 6!=6\times5\times4\times3\times2\times1\] so if you sub this in, we can easily simplify the equation \[(15\times14\times13\times12\times11\times10\times9!)\div(6!(9!))\] you can cancel out the 9! and be left w/\[(15\times14\times13\times12\times11\times10)\div(6!)\] then just simplify by using intuition

  16. katiebugg
    • 3 years ago
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    ohhh ok lol

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