Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
katiebugg
Group Title
I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected?
 2 years ago
 2 years ago
katiebugg Group Title
I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected?
 2 years ago
 2 years ago

This Question is Closed

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
dw:1343977571380:dw
 2 years ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
i have no idea
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
this might help :) dw:1343977665844:dw
 2 years ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
i think so how would i aply that
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
for your question n=15 and r=6 so dw:1343977816649:dw now can you solve it?
 2 years ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
why the !
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
oh it means factorial take "5!" for example 5!=5x4x3x2x1
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
so apply this to the current problem :o
 2 years ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
soo whats 15 c x 10
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
what do you think it is?
 2 years ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
idk am i multiplying it by the 15
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
answer is 5005...
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
but do you get how i got this?
 2 years ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
i want to say yess but i cant
 2 years ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
ok look :o \[15!=15\times14\times13\times12\times11\times......\times1 \] and\[9!=\times8\times7\times6\times5\times...1 and 6!=6\times5\times4\times3\times2\times1\] so if you sub this in, we can easily simplify the equation \[(15\times14\times13\times12\times11\times10\times9!)\div(6!(9!))\] you can cancel out the 9! and be left w/\[(15\times14\times13\times12\times11\times10)\div(6!)\] then just simplify by using intuition
 2 years ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
ohhh ok lol
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.