Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
katiebugg
Group Title
I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected?
 one year ago
 one year ago
katiebugg Group Title
I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected?
 one year ago
 one year ago

This Question is Closed

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
dw:1343977571380:dw
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
i have no idea
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
this might help :) dw:1343977665844:dw
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
i think so how would i aply that
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
for your question n=15 and r=6 so dw:1343977816649:dw now can you solve it?
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
why the !
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
oh it means factorial take "5!" for example 5!=5x4x3x2x1
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
so apply this to the current problem :o
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
soo whats 15 c x 10
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
what do you think it is?
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
idk am i multiplying it by the 15
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
answer is 5005...
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
but do you get how i got this?
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
i want to say yess but i cant
 one year ago

alexwee123 Group TitleBest ResponseYou've already chosen the best response.1
ok look :o \[15!=15\times14\times13\times12\times11\times......\times1 \] and\[9!=\times8\times7\times6\times5\times...1 and 6!=6\times5\times4\times3\times2\times1\] so if you sub this in, we can easily simplify the equation \[(15\times14\times13\times12\times11\times10\times9!)\div(6!(9!))\] you can cancel out the 9! and be left w/\[(15\times14\times13\times12\times11\times10)\div(6!)\] then just simplify by using intuition
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.0
ohhh ok lol
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.