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 2 years ago
I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected?
 2 years ago
I am going to choose 6 students out of the 15 who currently have A's to be mentors for the students who have C's or lower. How many ways can a group of 6 be selected?

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alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1343977571380:dw

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1this might help :) dw:1343977665844:dw

katiebugg
 2 years ago
Best ResponseYou've already chosen the best response.0i think so how would i aply that

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1for your question n=15 and r=6 so dw:1343977816649:dw now can you solve it?

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1oh it means factorial take "5!" for example 5!=5x4x3x2x1

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1so apply this to the current problem :o

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1what do you think it is?

katiebugg
 2 years ago
Best ResponseYou've already chosen the best response.0idk am i multiplying it by the 15

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1but do you get how i got this?

katiebugg
 2 years ago
Best ResponseYou've already chosen the best response.0i want to say yess but i cant

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1ok look :o \[15!=15\times14\times13\times12\times11\times......\times1 \] and\[9!=\times8\times7\times6\times5\times...1 and 6!=6\times5\times4\times3\times2\times1\] so if you sub this in, we can easily simplify the equation \[(15\times14\times13\times12\times11\times10\times9!)\div(6!(9!))\] you can cancel out the 9! and be left w/\[(15\times14\times13\times12\times11\times10)\div(6!)\] then just simplify by using intuition
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