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anonymous
 4 years ago
The sum of a geometric series is 2044. If the first term is 4 and the common ratio is 2, what is the final term in the sequence?
anonymous
 4 years ago
The sum of a geometric series is 2044. If the first term is 4 and the common ratio is 2, what is the final term in the sequence?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why @waterineyes any mistake

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry my mistake... Ha ha ha..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[2044 = 4[2^n 1]/(21)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0511 = 2^n  1 510 = 2^n

rsadhvika
 4 years ago
Best ResponseYou've already chosen the best response.0\(2044 = 4. \frac{2^{n}1}{21}\) \(2044 = 4. (2^{n}1)\) \(511 = 2^{n}1\) \(512 = 2^{n}\) \(2^9 = 2^{n}\) 9=n

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0subs in an = a * r^(n1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\large 2^n = 512 \implies 2^n = 2^9 \implies \color{green}{n = 9}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can replace n here by 9 @Yahoo!
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