A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
The sum of an arithmetic series is 1356 and the first term is 1. If the common difference is 5, how many terms are in the sequence?
 2 years ago
The sum of an arithmetic series is 1356 and the first term is 1. If the common difference is 5, how many terms are in the sequence?

This Question is Closed

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.0@katiebugg Sum of n terms is given 1356 First term \(a_1=1\) and common difference=5 we know that sum to n terms is given as \[S_n=\frac{n}{2}(a_1+a_n)\] \(a_n\) is the last term Do you get till this?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.0we know \(a_n\) is given as \[a_n=a_1+(n1)d\] d=common difference n=no. of terms so sum will become \[S_n=\frac n2 (a_1+a_1+(n1)d)\] now pluigin the numbers here and post what do you get, will you?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.