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The sum of an arithmetic series is 1356 and the first term is 1. If the common difference is 5, how many terms are in the sequence?
 one year ago
 one year ago
The sum of an arithmetic series is 1356 and the first term is 1. If the common difference is 5, how many terms are in the sequence?
 one year ago
 one year ago

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ash2326Best ResponseYou've already chosen the best response.0
@katiebugg Sum of n terms is given 1356 First term \(a_1=1\) and common difference=5 we know that sum to n terms is given as \[S_n=\frac{n}{2}(a_1+a_n)\] \(a_n\) is the last term Do you get till this?
 one year ago

ash2326Best ResponseYou've already chosen the best response.0
we know \(a_n\) is given as \[a_n=a_1+(n1)d\] d=common difference n=no. of terms so sum will become \[S_n=\frac n2 (a_1+a_1+(n1)d)\] now pluigin the numbers here and post what do you get, will you?
 one year ago
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