solve

- anonymous

solve

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- schrodinger

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- lgbasallote

sure

- anonymous

\[c _{18 12}\]

- lgbasallote

?

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## More answers

- anonymous

c=0

- lgbasallote

judging from your past questions...this has something to do with arithmetic/geometric sequence?

- lgbasallote

is that a wolfram answer again?

- anonymous

yeah it does

- ash2326

@katiebugg Please don't post a new question until you are done with your previous one.
Thanks :)

- anonymous

sorry i got the answer

- lgbasallote

i still dont get what this question means...and why the heck do people LOVE attaching "thanks" at the end of their statements o.O

- anonymous

i dont get it eaither... the question that is

- ash2326

@katiebugg I can see that you've posted similar questions. Did you understand the concepts involved?

- ash2326

@lgbasallote to sound polite
thanks:)

- anonymous

kinnda butt not really been upp all night doing this soooo

- lgbasallote

dont use it on me -_- it creeps and freaks me out

- anonymous

hahaha

- lgbasallote

@katiebugg are there any other conditions or phrases that come along with the question?

- ash2326

@katiebugg it's better to take rest now and start afresh tomorrow.

- anonymous

nope juse evaluate

- anonymous

and this has to bee done 2mrw sooo

- lgbasallote

can you write it in bigger text?

- anonymous

its a C then 18 and 12

- lgbasallote

but where are 18 and 12..beside C? below C? some of the placements are VERY important

- anonymous

umm subscripts

- ash2326

@katiebugg are you learning combinations?

- anonymous

yess!!!!!!

- lgbasallote

OH...that makes more sense =_=

- anonymous

sorry

- lgbasallote

\[\huge nCr = \frac{n!}{r!(n-r)!}\]
does that help?

- anonymous

ahhhhhhhh!!!!!!!! no

- lgbasallote

for example
\[3C2 = \frac{3!}{2!(3-2)!}\]

- lgbasallote

now does it help?

- anonymous

this is last one then get to go to bed and no ima still lost :(

- lgbasallote

here's another one...
\[12C10 \implies \frac{12!}{10!(12-10)!} \implies \frac{12!}{10!2!} \implies \frac{12 \times 11 \times \cancel{10!}}{\cancel{10!} 2!} \implies \frac{12 \times 11}{2 \times 1}\]
does that help?

- anonymous

how do i know were the 18 and the 12 go

- lgbasallote

the bigger one is always in the numerator

- lgbasallote

that's just how i remember it heh

- anonymous

k thaks!!!!!!!!

- lgbasallote

welcome ^_^

- lgbasallote

spamming random examples of solutions really does help huh...

- anonymous

:( no i got like the first step and now ima lost

- lgbasallote

oh btw....you're online schooled right?

- anonymous

just for summer i wanted to jump ahead
soo i took a class

- lgbasallote

hah i knew it..i could tell based on the random jumping of topics haha lol...anyway back to your question

- lgbasallote

what did you get for the first step?

- anonymous

umm 18/12(6)

- lgbasallote

hmmm you do mean \[\frac{18!}{12!6!}\]
right?

- anonymous

and u watchin my questions hahah creeper :P and yess

- lgbasallote

the exclamation points are very crucial...

- lgbasallote

heh it's my avatar duty :p

- anonymous

love that show ahahaha

- lgbasallote

okay here's a hint for you
\[\small 18! \implies 18 \times 17 \times 16 \times 15 \times 14 \times 13\times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\]
\[12! \implies 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\]
\[6! \implies 6 \times 5 \times 4 \times 3 \times 2 \times 1\]
does that help?

- anonymous

just told me what the !!! do right

- lgbasallote

hmm?

- lgbasallote

okay here's another hint \[\large \frac{18!}{12! 6!} \implies \frac{18 \times 17 \times 16 \times 15 \times 14 \times 13 \times 12!}{(12!)(6!)}\]
does that help more?

- lgbasallote

look for something you can cancel..

- anonymous

and then

- lgbasallote

cancel the cancellable

- anonymous

ok i think

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