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Can anyone give me the solutions for the practice quiz 1 Spring 2011 or some feedback on my answers please?
1.1 true
1.2 false
1.3 true
1.4 false
1.5 false
3.2) O(n) n=length(cyphertext)
6.2)No. In python, the elements of a dictionaire (as is d) don't have an order. Thus, it is not possible to predict which key of d will be evaluated first as k. If ''b'' is evaluated first, when a is evaluated, y will remain as "b" beucase d["b"]=d["a". The opposite will happen if "c" is evaluated first.
 one year ago
 one year ago
Can anyone give me the solutions for the practice quiz 1 Spring 2011 or some feedback on my answers please? 1.1 true 1.2 false 1.3 true 1.4 false 1.5 false 3.2) O(n) n=length(cyphertext) 6.2)No. In python, the elements of a dictionaire (as is d) don't have an order. Thus, it is not possible to predict which key of d will be evaluated first as k. If ''b'' is evaluated first, when a is evaluated, y will remain as "b" beucase d["b"]=d["a". The opposite will happen if "c" is evaluated first.
 one year ago
 one year ago

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David_NovoBest ResponseYou've already chosen the best response.0
6.3)No. If the string is an empty string, it will generate an error because, as there will occur no iterations, there won't be a value assigned to y. 4) if len(v1)<=len(v2): big=v2 small=v1 else: big=v1 small=v2 v3=[0]*len(big) for i in range(len(small)): v3[i] = big[i]+small[i] v3[(i+1):] = big[(i+1):] if v3==0: return [] else: return v3
 one year ago

David_NovoBest ResponseYou've already chosen the best response.0
Can anyone at least tell me if the following is True or False: 'When Newton’s method is used to find the root of a polynomial, the order of complexity is quadratic in the number of terms in the polynomial. '
 one year ago

sakhBest ResponseYou've already chosen the best response.0
TA goes through answers in recitation.
 one year ago

David_NovoBest ResponseYou've already chosen the best response.0
No, he doesn't. He goes through the answers to the Quiz. I'm looking for the answers to the Practice Quiz.
 one year ago
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