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(tanTheta+secTheta1)/(tanThetasecTheta+1) = (1+sinTheta)/(cosTheta)
Prove that the two expressions are equal.
 one year ago
 one year ago
(tanTheta+secTheta1)/(tanThetasecTheta+1) = (1+sinTheta)/(cosTheta) Prove that the two expressions are equal.
 one year ago
 one year ago

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vinrarBest ResponseYou've already chosen the best response.0
tanTheta = sinTheta/cosTheta and secTheta=1/cosTheta substitute them
 one year ago

SnapbackliveBest ResponseYou've already chosen the best response.0
This is an identity. Right side = 0 Left side: = secθ  sinθtanθ  cosθ Change tanθ to sinθ/cosθ secθ  sin^2θ/cosθ  cosθ Multiply the cosθ by cosθ/cosθ and change the secθ to 1/cosθ (1/cosθ)  (sin^2θ/cosθ)  (cos^2θ/cosθ) You now have a common denominator: [1  sin^2θ  cos^2θ] / [cosθ] Factor out a negative in the numerator [1  (sin^2θ + cos^2θ)] / [cosθ] sin^2θ + cos^2θ = 1 [1  (1)] / [cosθ] 0 / [cosθ] 0 So LS = RS, QED.
 one year ago
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