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asdfghjkl8063

  • 3 years ago

(tanTheta+secTheta-1)/(tanTheta-secTheta+1) = (1+sinTheta)/(cosTheta) Prove that the two expressions are equal.

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  1. vinrar
    • 3 years ago
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    tanTheta = sinTheta/cosTheta and secTheta=1/cosTheta substitute them

  2. vinrar
    • 3 years ago
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    done substituting?

  3. Snapbacklive
    • 3 years ago
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    This is an identity. Right side = 0 Left side: = secθ - sinθtanθ - cosθ Change tanθ to sinθ/cosθ secθ - sin^2θ/cosθ - cosθ Multiply the cosθ by cosθ/cosθ and change the secθ to 1/cosθ (1/cosθ) - (sin^2θ/cosθ) - (cos^2θ/cosθ) You now have a common denominator: [1 - sin^2θ - cos^2θ] / [cosθ] Factor out a negative in the numerator [1 - (sin^2θ + cos^2θ)] / [cosθ] sin^2θ + cos^2θ = 1 [1 - (1)] / [cosθ] 0 / [cosθ] 0 So LS = RS, QED.

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