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asdfghjkl8063
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(tanTheta+secTheta1)/(tanThetasecTheta+1) = (1+sinTheta)/(cosTheta)
Prove that the two expressions are equal.
 one year ago
 one year ago
asdfghjkl8063 Group Title
(tanTheta+secTheta1)/(tanThetasecTheta+1) = (1+sinTheta)/(cosTheta) Prove that the two expressions are equal.
 one year ago
 one year ago

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vinrar Group TitleBest ResponseYou've already chosen the best response.0
tanTheta = sinTheta/cosTheta and secTheta=1/cosTheta substitute them
 one year ago

vinrar Group TitleBest ResponseYou've already chosen the best response.0
done substituting?
 one year ago

Snapbacklive Group TitleBest ResponseYou've already chosen the best response.0
This is an identity. Right side = 0 Left side: = secθ  sinθtanθ  cosθ Change tanθ to sinθ/cosθ secθ  sin^2θ/cosθ  cosθ Multiply the cosθ by cosθ/cosθ and change the secθ to 1/cosθ (1/cosθ)  (sin^2θ/cosθ)  (cos^2θ/cosθ) You now have a common denominator: [1  sin^2θ  cos^2θ] / [cosθ] Factor out a negative in the numerator [1  (sin^2θ + cos^2θ)] / [cosθ] sin^2θ + cos^2θ = 1 [1  (1)] / [cosθ] 0 / [cosθ] 0 So LS = RS, QED.
 one year ago
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