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anonymous
 4 years ago
P(x)=\[x^4x^37x^2+x+6\]
Solve P(x)>0
anonymous
 4 years ago
P(x)=\[x^4x^37x^2+x+6\] Solve P(x)>0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0simplify the equation into its factors one factor being x1 and find other factors then write down the domain of the factors, and you'll see the range is positive in certain domain that's the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0factorise it and find zeros and use tabe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0table method not tabe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya what is the table method?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0table method: sit down at the table with pencil and paper :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I will do for easy one ok suppose dw:1344005362435:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you find the zeros then use synthetic division to reduce it to a smaller factor?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here dw:1344005426187:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0can you use calculus?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0x^4 + .... has the shapedw:1344005576425:dw knowing the min and max parts would be useful

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1344005474076:dw now using table dw:1344005508829:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so from the table we getdw:1344005614786:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0got it @strawberry_militia

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use this similar method to solve your question @strawberry_militia

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0well, a quick trial and error gives me one zero: f(0) = 6 f(1) = 0

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0that should reduce it to a cubic

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have found the factors.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0then plot them on a number line and take test point between the zeros to determine signage

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0write down the factors in coordinates form like if the four factors are a,b,c,d and a<b<c<d then write it as (infinity,a) (a,b) (b,c) and (c,d)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0to inf and +inf should be positive just by the nature of the poly

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and (d,infinity) then substitute a value in between (infinity ,a) and check it is positive or not similiarly do for (a,b) (b,c) and (c,d) and (d,infinity)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so when you get a positive value..that is your required range

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I will try it out. thanks for all your responses.
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