anonymous
  • anonymous
P(x)=\[x^4-x^3-7x^2+x+6\] Solve P(x)>0
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
simplify the equation into its factors one factor being x-1 and find other factors then write down the domain of the factors, and you'll see the range is positive in certain domain that's the answer
anonymous
  • anonymous
factorise it and find zeros and use tabe
anonymous
  • anonymous
table method not tabe

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anonymous
  • anonymous
@sauravshakya what is the table method?
amistre64
  • amistre64
table method: sit down at the table with pencil and paper :)
anonymous
  • anonymous
I will do for easy one ok suppose |dw:1344005362435:dw|
anonymous
  • anonymous
can you find the zeros then use synthetic division to reduce it to a smaller factor?
anonymous
  • anonymous
here |dw:1344005426187:dw|
amistre64
  • amistre64
can you use calculus?
anonymous
  • anonymous
no
amistre64
  • amistre64
x^4 + .... has the shape|dw:1344005576425:dw| knowing the min and max parts would be useful
anonymous
  • anonymous
|dw:1344005474076:dw| now using table |dw:1344005508829:dw|
anonymous
  • anonymous
so from the table we get|dw:1344005614786:dw|
anonymous
  • anonymous
got it @strawberry_militia
anonymous
  • anonymous
use this similar method to solve your question @strawberry_militia
amistre64
  • amistre64
well, a quick trial and error gives me one zero: f(0) = 6 f(1) = 0
amistre64
  • amistre64
that should reduce it to a cubic
anonymous
  • anonymous
I have found the factors.
amistre64
  • amistre64
then plot them on a number line and take test point between the zeros to determine signage
anonymous
  • anonymous
write down the factors in coordinates form like if the four factors are a,b,c,d and a
amistre64
  • amistre64
to -inf and +inf should be positive just by the nature of the poly
anonymous
  • anonymous
and (d,infinity) then substitute a value in between (-infinity ,a) and check it is positive or not similiarly do for (a,b) (b,c) and (c,d) and (d,infinity)
anonymous
  • anonymous
so when you get a positive value..that is your required range
anonymous
  • anonymous
I will try it out. thanks for all your responses.

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