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strawberry_militia
 3 years ago
P(x)=\[x^4x^37x^2+x+6\]
Solve P(x)>0
strawberry_militia
 3 years ago
P(x)=\[x^4x^37x^2+x+6\] Solve P(x)>0

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vinrar
 3 years ago
Best ResponseYou've already chosen the best response.1simplify the equation into its factors one factor being x1 and find other factors then write down the domain of the factors, and you'll see the range is positive in certain domain that's the answer

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2factorise it and find zeros and use tabe

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2table method not tabe

strawberry_militia
 3 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya what is the table method?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0table method: sit down at the table with pencil and paper :)

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2I will do for easy one ok suppose dw:1344005362435:dw

nickhouraney
 3 years ago
Best ResponseYou've already chosen the best response.0can you find the zeros then use synthetic division to reduce it to a smaller factor?

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2here dw:1344005426187:dw

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0can you use calculus?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0x^4 + .... has the shapedw:1344005576425:dw knowing the min and max parts would be useful

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1344005474076:dw now using table dw:1344005508829:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2so from the table we getdw:1344005614786:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2got it @strawberry_militia

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2use this similar method to solve your question @strawberry_militia

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0well, a quick trial and error gives me one zero: f(0) = 6 f(1) = 0

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0that should reduce it to a cubic

strawberry_militia
 3 years ago
Best ResponseYou've already chosen the best response.0I have found the factors.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0then plot them on a number line and take test point between the zeros to determine signage

vinrar
 3 years ago
Best ResponseYou've already chosen the best response.1write down the factors in coordinates form like if the four factors are a,b,c,d and a<b<c<d then write it as (infinity,a) (a,b) (b,c) and (c,d)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0to inf and +inf should be positive just by the nature of the poly

vinrar
 3 years ago
Best ResponseYou've already chosen the best response.1and (d,infinity) then substitute a value in between (infinity ,a) and check it is positive or not similiarly do for (a,b) (b,c) and (c,d) and (d,infinity)

vinrar
 3 years ago
Best ResponseYou've already chosen the best response.1so when you get a positive value..that is your required range

strawberry_militia
 3 years ago
Best ResponseYou've already chosen the best response.0I will try it out. thanks for all your responses.
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