qasaali
integrate (2x^31)^2(6x^2)



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lgbasallote
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let u = 2x^3  1
du = 6x^2
so therefore the integral just becomes \[\int u^2 du\]
does that help?

qasaali
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hey continue it dont stop u r on the right track

lgbasallote
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that's already an easy integral...do you still need help?

Snapbacklive
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24x^824x^5+6x^2

WLB250219
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\[(2x^31)^2(6x^2\]

amistre64
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i simple way is just to expand it all out into a single polynomial and integrate it term for term

amistre64
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but if method is "defined", then lgbas is prolly best

WLB250219
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true so in this question you can say \[49 * 12x\]

WLB250219
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dw:1344008290718:dwthat will dije you the answer that you are looking for

WLB250219
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dw:1344008471163:dw

WLB250219
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you can do it i believe you can you are smart !!