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integrate (2x^3-1)^2(6x^2)

Mathematics
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let u = 2x^3 - 1 du = 6x^2 so therefore the integral just becomes \[\int u^2 du\] does that help?
hey continue it dont stop u r on the right track
that's already an easy integral...do you still need help?

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Other answers:

24x^8-24x^5+6x^2
\[(2x^3-1)^2(6x^2\]
i simple way is just to expand it all out into a single polynomial and integrate it term for term
but if method is "defined", then lgbas is prolly best
true so in this question you can say \[49 * 12x\]
|dw:1344008290718:dw|that will dije you the answer that you are looking for
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you can do it i believe you can you are smart !!

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