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vinrar
 2 years ago
Best ResponseYou've already chosen the best response.0(a+b)^3 = a^3 + b^3 + 3ab(a+b)

nitz
 2 years ago
Best ResponseYou've already chosen the best response.2see there are two ways...... either expand the cube and multiply/.... or use binomial expansion (x+3)^4.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0\[\large{(x+3)(x+3)^3}\] \[\large{(a+b)^3=a^3+b^3+3ab(a+b)>identity}\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0@cdelomas have u learnt binomial theorem?

nickhouraney
 2 years ago
Best ResponseYou've already chosen the best response.0binomial theorem or pascals triangle will work

cdelomas
 2 years ago
Best ResponseYou've already chosen the best response.0i will check it out and comeback

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0forget binomial theorem : \[\large{(x+3)(x+3)^3=(x+3){(x+3)(x+3)(x+3)}}\] \[\large{(x+3)^2(x+3)^2}\] \[\large{(x+3)^2=x^2+3^2+2(x)(3)}\] \[\large{x^2+9+6x}\] \[\large{(x^2+9+6x)(x^2+9+6x)}\] \[\large{x^4+9x^2+6x^3+9x^2+81+54x+6x^3+54x+36x^2}\] \[\large{x^4+12x^3+54x^2+108x+81}\]
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