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vinrar Group TitleBest ResponseYou've already chosen the best response.0
(a+b)^3 = a^3 + b^3 + 3ab(a+b)
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.2
see there are two ways...... either expand the cube and multiply/.... or use binomial expansion (x+3)^4.
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
\[\large{(x+3)(x+3)^3}\] \[\large{(a+b)^3=a^3+b^3+3ab(a+b)>identity}\]
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
@cdelomas have u learnt binomial theorem?
 one year ago

nickhouraney Group TitleBest ResponseYou've already chosen the best response.0
binomial theorem or pascals triangle will work
 one year ago

cdelomas Group TitleBest ResponseYou've already chosen the best response.0
what is that
 one year ago

nickhouraney Group TitleBest ResponseYou've already chosen the best response.0
http://www.mathsisfun.com/pascalstriangle.html
 one year ago

cdelomas Group TitleBest ResponseYou've already chosen the best response.0
i will check it out and comeback
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
forget binomial theorem : \[\large{(x+3)(x+3)^3=(x+3){(x+3)(x+3)(x+3)}}\] \[\large{(x+3)^2(x+3)^2}\] \[\large{(x+3)^2=x^2+3^2+2(x)(3)}\] \[\large{x^2+9+6x}\] \[\large{(x^2+9+6x)(x^2+9+6x)}\] \[\large{x^4+9x^2+6x^3+9x^2+81+54x+6x^3+54x+36x^2}\] \[\large{x^4+12x^3+54x^2+108x+81}\]
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
got it ?
 one year ago
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