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cdelomas

(x+3) (x+3)^3 simplify

  • one year ago
  • one year ago

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  1. vinrar
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    (a+b)^3 = a^3 + b^3 + 3ab(a+b)

    • one year ago
  2. nitz
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    see there are two ways...... either expand the cube and multiply/.... or use binomial expansion (x+3)^4.

    • one year ago
  3. mathslover
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    \[\large{(x+3)(x+3)^3}\] \[\large{(a+b)^3=a^3+b^3+3ab(a+b)->identity}\]

    • one year ago
  4. mathslover
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    @cdelomas have u learnt binomial theorem?

    • one year ago
  5. cdelomas
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    no

    • one year ago
  6. nickhouraney
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    binomial theorem or pascals triangle will work

    • one year ago
  7. cdelomas
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    what is that

    • one year ago
  8. nickhouraney
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    http://www.mathsisfun.com/pascals-triangle.html

    • one year ago
  9. cdelomas
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    i will check it out and comeback

    • one year ago
  10. mathslover
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    forget binomial theorem : \[\large{(x+3)(x+3)^3=(x+3){(x+3)(x+3)(x+3)}}\] \[\large{(x+3)^2(x+3)^2}\] \[\large{(x+3)^2=x^2+3^2+2(x)(3)}\] \[\large{x^2+9+6x}\] \[\large{(x^2+9+6x)(x^2+9+6x)}\] \[\large{x^4+9x^2+6x^3+9x^2+81+54x+6x^3+54x+36x^2}\] \[\large{x^4+12x^3+54x^2+108x+81}\]

    • one year ago
  11. mathslover
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    got it ?

    • one year ago
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