mathdummy4
i just need help with the formula here...find the number of ways in which each committee can be selected.
3 people from a group of 5



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vinrar
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5C3

lgbasallote
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the formula would be combinations \[nCr = \frac{n!}{r!(nr)!}\]
does that help?

mathdummy4
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so well thats what i did...5!/(2!3!)...and the answer was wrong

lgbasallote
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that's because it's \[\frac{5!}{3!2!}\]not minus

amistre64
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5P3

3!

amistre64
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5.4.3 5.4
 =  = 20/2
3.2.1 2

mathdummy4
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oo okay oops!...thanks:)