## anonymous 4 years ago i just need help with the formula here...find the number of ways in which each committee can be selected. 3 people from a group of 5

1. anonymous

5C3

2. anonymous

the formula would be combinations $nCr = \frac{n!}{r!(n-r)!}$ does that help?

3. anonymous

so well thats what i did...5!/(2!-3!)...and the answer was wrong

4. anonymous

that's because it's $\frac{5!}{3!2!}$not minus

5. amistre64

5P3 ---- 3!

6. amistre64

5.4.3 5.4 ----- = --- = 20/2 3.2.1 2

7. anonymous

oo okay oops!...thanks:)