Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mathdummy4

  • 3 years ago

i just need help with the formula here...find the number of ways in which each committee can be selected. 3 people from a group of 5

  • This Question is Closed
  1. vinrar
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    5C3

  2. lgbasallote
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the formula would be combinations \[nCr = \frac{n!}{r!(n-r)!}\] does that help?

  3. mathdummy4
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so well thats what i did...5!/(2!-3!)...and the answer was wrong

  4. lgbasallote
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that's because it's \[\frac{5!}{3!2!}\]not minus

  5. amistre64
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    5P3 ---- 3!

  6. amistre64
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    5.4.3 5.4 ----- = --- = 20/2 3.2.1 2

  7. mathdummy4
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oo okay oops!...thanks:)

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy