i just need help with the formula here...find the number of ways in which each committee can be selected. 3 people from a group of 5

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i just need help with the formula here...find the number of ways in which each committee can be selected. 3 people from a group of 5

Mathematics
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5C3
the formula would be combinations \[nCr = \frac{n!}{r!(n-r)!}\] does that help?
so well thats what i did...5!/(2!-3!)...and the answer was wrong

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that's because it's \[\frac{5!}{3!2!}\]not minus
5P3 ---- 3!
5.4.3 5.4 ----- = --- = 20/2 3.2.1 2
oo okay oops!...thanks:)

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