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mathdummy4 Group Title

i just need help with the formula here...find the number of ways in which each committee can be selected. 3 people from a group of 5

  • one year ago
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  1. vinrar Group Title
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    5C3

    • one year ago
  2. lgbasallote Group Title
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    the formula would be combinations \[nCr = \frac{n!}{r!(n-r)!}\] does that help?

    • one year ago
  3. mathdummy4 Group Title
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    so well thats what i did...5!/(2!-3!)...and the answer was wrong

    • one year ago
  4. lgbasallote Group Title
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    that's because it's \[\frac{5!}{3!2!}\]not minus

    • one year ago
  5. amistre64 Group Title
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    5P3 ---- 3!

    • one year ago
  6. amistre64 Group Title
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    5.4.3 5.4 ----- = --- = 20/2 3.2.1 2

    • one year ago
  7. mathdummy4 Group Title
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    oo okay oops!...thanks:)

    • one year ago
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