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mathdummy4
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i just need help with the formula here...find the number of ways in which each committee can be selected.
3 people from a group of 5
 one year ago
 one year ago
mathdummy4 Group Title
i just need help with the formula here...find the number of ways in which each committee can be selected. 3 people from a group of 5
 one year ago
 one year ago

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lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
the formula would be combinations \[nCr = \frac{n!}{r!(nr)!}\] does that help?
 one year ago

mathdummy4 Group TitleBest ResponseYou've already chosen the best response.0
so well thats what i did...5!/(2!3!)...and the answer was wrong
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
that's because it's \[\frac{5!}{3!2!}\]not minus
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
5P3  3!
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
5.4.3 5.4  =  = 20/2 3.2.1 2
 one year ago

mathdummy4 Group TitleBest ResponseYou've already chosen the best response.0
oo okay oops!...thanks:)
 one year ago
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