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any ideas?

total number of permutations when a dice is rolled 8 times = 6^8

\[3/48\]= x

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how did you get 3/48??

At least 7 even is the same as at most 1 odd.
0 odd = 1/256
1 odd = 8/256
Total = 9/256

6times 8 is 48 and divide by 3 and you will get 16 so the answer is 1/16

okay...so what if you were looking for 8 odd numbers? wouldn't it be the same process?

yes

well i got the same answer..1/16...is that right?

yes

You have to have 7 throws even and the 8th one can be either.
\[
\frac 1{2^7} 8=\frac 1 {16}
\]

You multiply by 8 to count where the even or odd throw is.

|dw:1344014586415:dw|yes

thanks:)

your welcome

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