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Alright. I'm still a bit confused...would I do them all separately?

plugin into wolfram ... something interesting there

lol...it is a bit interesting...I need to know how to do these without wolfram though...

Is that really what I do?

i'm not sure .... though this technique seems pretty promising

But all that results in is the removal of the absolute value no?

yep ... take square and see |dw:1344019775207:dw|

sorry .. my bad

|dw:1344020042743:dw|

looks like this is going to be quite difficult ...

|dw:1344020241753:dw|

for x is positive.

Well, turns out that sai at the beginning was correct...you just work out the 4 different cases...

I found the solution set...

Thanks for trying though...

for x is negative, |dw:1344020308613:dw|

check the value for a = 3, which is less than 30|dw:1344020674321:dw|

|dw:1344020722686:dw|

|dw:1344020797357:dw|

Yup. I get it now. We just test out all 4 possibilities and combine the inequalities. Thank you :)

well ... the best would be do see carefully how it takes the least effort ...