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Calcmathlete
 3 years ago
Find the solution set of the inequality: 2x + 5 + 4x + 7 < 30
How would you do this kind of problem? I'm not familiar with how to do it when there are two separate absolute values...
Calcmathlete
 3 years ago
Find the solution set of the inequality: 2x + 5 + 4x + 7 < 30 How would you do this kind of problem? I'm not familiar with how to do it when there are two separate absolute values...

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sai1234
 3 years ago
Best ResponseYou've already chosen the best response.0u can write 2x + 5 as2x + 5 or (2x + 5) like that 4x + 7 as(4x + 7) or (4x + 7) so totally there as 4 possibilities

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Alright. I'm still a bit confused...would I do them all separately?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1plugin into wolfram ... something interesting there

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0lol...it is a bit interesting...I need to know how to do these without wolfram though...

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Is that really what I do?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1i'm not sure .... though this technique seems pretty promising

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0But all that results in is the removal of the absolute value no?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1yep ... take square and see dw:1344019775207:dw

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0I am so confused...not going to lie...if you take the square of both sides, wouldn't you end up with the second side: dw:1344019964409:dw and where did the absolute value come back in?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1344020042743:dw

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1looks like this is going to be quite difficult ...

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah...my teacher said that there was a very simple trick to this, but she never had the opportunity to teach it to me, so I'm just stuck on what to do...

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1344020241753:dw

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Well, turns out that sai at the beginning was correct...you just work out the 4 different cases...

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0I found the solution set...

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks for trying though...

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1for x is negative, dw:1344020308613:dw

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1check the value for a = 3, which is less than 30dw:1344020674321:dw

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1344020722686:dw

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1344020797357:dw

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Yup. I get it now. We just test out all 4 possibilities and combine the inequalities. Thank you :)

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1well ... the best would be do see carefully how it takes the least effort ...
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