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Find the solution set of the inequality: 2x + 5 + 4x + 7 < 30
How would you do this kind of problem? I'm not familiar with how to do it when there are two separate absolute values...
 one year ago
 one year ago
Find the solution set of the inequality: 2x + 5 + 4x + 7 < 30 How would you do this kind of problem? I'm not familiar with how to do it when there are two separate absolute values...
 one year ago
 one year ago

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sai1234Best ResponseYou've already chosen the best response.0
u can write 2x + 5 as2x + 5 or (2x + 5) like that 4x + 7 as(4x + 7) or (4x + 7) so totally there as 4 possibilities
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Alright. I'm still a bit confused...would I do them all separately?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
plugin into wolfram ... something interesting there
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
lol...it is a bit interesting...I need to know how to do these without wolfram though...
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Is that really what I do?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
i'm not sure .... though this technique seems pretty promising
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
But all that results in is the removal of the absolute value no?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
yep ... take square and see dw:1344019775207:dw
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
I am so confused...not going to lie...if you take the square of both sides, wouldn't you end up with the second side: dw:1344019964409:dw and where did the absolute value come back in?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1344020042743:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
looks like this is going to be quite difficult ...
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Yeah...my teacher said that there was a very simple trick to this, but she never had the opportunity to teach it to me, so I'm just stuck on what to do...
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1344020241753:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
for x is positive.
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Well, turns out that sai at the beginning was correct...you just work out the 4 different cases...
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
I found the solution set...
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Thanks for trying though...
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
for x is negative, dw:1344020308613:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
check the value for a = 3, which is less than 30dw:1344020674321:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1344020722686:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1344020797357:dw
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Yup. I get it now. We just test out all 4 possibilities and combine the inequalities. Thank you :)
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
well ... the best would be do see carefully how it takes the least effort ...
 one year ago
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