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in 3D, why theta = l/r^2. in 2D theta = l/r. im not good with noneuclidean geometries.. can somebody pls show a proof or give a good link pls
 one year ago
 one year ago
in 3D, why theta = l/r^2. in 2D theta = l/r. im not good with noneuclidean geometries.. can somebody pls show a proof or give a good link pls
 one year ago
 one year ago

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experimentXBest ResponseYou've already chosen the best response.1
due to the nature of conservation of flux
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
its related to 1/r^2 relationship ?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
yeah i believe everything that propagates in 3D follows that
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
if universe were flat ... the law of gravity would be F = Gm1m2/r instead of r^2 < at least that's how i'm thinking these days
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
yes i get that.. im looking for a proof. i got stuck while refreshing electrostatics when i come across flux around point charge
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
i think Gauss law is fine ...
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
gauss law is next topic .... ill see if it gets addressed .. thank you :)
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
there maynot be any derivation. its just a fact this 1/r^2 relation for 3D model
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
this is very easy to visualize ... in terms of light. the intensity of light decreases by /r^2 ... because light diverges in all 3d directions. dw:1344027074813:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1344027132708:dw the total light must be same in both surface.
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
let's say ... this is due to the geometry of the sphere (surface) in 3D ... and the conservation of theorem.
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
i see that... total light has to escape throuh both the spherical surfaces. its same light that goes out
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
yep ... or i must be stupid.
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
this is a law is it.. we cannot derive 1/r^2 relationship... like we derive 1/r in circle for theta
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
everything seems new.. now when i open my books again
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
what do you mean by 1/r in circle ... can you elaborate a bit?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
my suggestion ... never open a book :D
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
il get back... read some more. actually im looking for some derivation of relation between angle and area for a sphere
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
you need solid angle
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.0
yeah looks like we need to consider surface area of sphere... i think im getting it now.. il try... thank you :D
 one year ago
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