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If a is not 0, a/x=b/y, and a/2b=c(3*(x/y), what is the value of c?



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dw:1344036321046:dw
Just the 2 equations on the top

lgbasallote
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so \[\huge a = \frac{bx}{y}\]
agree?

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yep

lgbasallote
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so if i substitute that into the second equation i will have \[\huge \frac{\frac{bx}{y}}{2b} = \frac{3xc}{y}\]
you following?

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yup

lgbasallote
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so again i simplify \[\huge \frac{bx}{2by} = \frac{3xc}{y}\]
do you see the next step now?

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ohhh You can do that?

lgbasallote
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which one?

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bx/y/2b=bx/2by

lgbasallote
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\[\huge \frac{\frac{bx}{y}}{2b} \implies \frac{bx}{y} \times \frac{1}{2b} \implies \frac{bx}{2by}\]
see it now?

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Okay.

lgbasallote
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so do you see what you can do in \[\huge \frac{bx}{2by} = \frac{3xc}{y}\]

lgbasallote
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hint:
think of cancellation

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I got 6xc=x

lgbasallote
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you can simplify more

lgbasallote
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both sides have x right?

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6c=0?

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c=0?

lgbasallote
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x/x is 0?

lgbasallote
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a number divided by itself is 0?`

lgbasallote
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is 2/2 = 0?
3/3 = 0?
4/4 = 0?

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one.

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same thing :/

lgbasallote
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right

lgbasallote
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it's not same thing

lgbasallote
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write it down and you'll see it's not the same thing

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1=0

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c=1/6, then.

lgbasallote
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correct

lgbasallote
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and 1 is not equal to 0

lgbasallote
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anyway c = 1/6

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thanks

lgbasallote
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welcome ^_^