If a is not 0, a/x=b/y, and a/2b=c(3*(x/y), what is the value of c?

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If a is not 0, a/x=b/y, and a/2b=c(3*(x/y), what is the value of c?

Mathematics
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|dw:1344036321046:dw| Just the 2 equations on the top
so \[\huge a = \frac{bx}{y}\] agree?
yep

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so if i substitute that into the second equation i will have \[\huge \frac{\frac{bx}{y}}{2b} = \frac{3xc}{y}\] you following?
yup
so again i simplify \[\huge \frac{bx}{2by} = \frac{3xc}{y}\] do you see the next step now?
ohhh You can do that?
which one?
bx/y/2b=bx/2by
\[\huge \frac{\frac{bx}{y}}{2b} \implies \frac{bx}{y} \times \frac{1}{2b} \implies \frac{bx}{2by}\] see it now?
Okay.
so do you see what you can do in \[\huge \frac{bx}{2by} = \frac{3xc}{y}\]
hint: think of cancellation
I got 6xc=x
you can simplify more
both sides have x right?
6c=0?
c=0?
x/x is 0?
a number divided by itself is 0?`
is 2/2 = 0? 3/3 = 0? 4/4 = 0?
one.
same thing :/
right
it's not same thing
write it down and you'll see it's not the same thing
1=0
c=1/6, then.
correct
and 1 is not equal to 0
anyway c = 1/6
thanks
welcome ^_^

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