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where do you need help?

first of all the parabola definitely opens up indicated by x^2

I need helping showing work for vertex and x intercept

ok, to find the vertex(turning point) simply we need to factorize the equation first.

do you know how to do that?

And if the vertex is max or min. And no I do not.

vertex is definitely a minimum because the graph is opening upwards.

|dw:1344039832324:dw|

that's an example

it's opening upwards so there's a minimum.

opposite applies so opening downwards, there is a maximum

okay.

guys you mind if I help here too?

The more the better!

look at the graph that has been drawn.

no, I could use the help please stay

I can not draw like you

Please help me find the vertex and x intercept!

okay

first I am trying to help with this question only, what do you know about the vertex already?

nothing really.

that is alright, let's take this slow than.

one min

in order to what you are asking we must do something to complete square

let me ask have you ever done this before for finding the vertex?

nope

please watch this you tub video here :
► 4:51► 4:51
www.youtube.com/watch?v=niHBt4rkavA

I got it, thank you!

no problem glad I could help out..