anonymous
  • anonymous
For y = x2 − 4x + 3, Determine if the parabola opens up or down. State if the vertex will be a maximum or minimum. Find the vertex. Find the x-intercepts. Describe the graph of the equation. PLEASE HELP! Need to finish this..
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
where do you need help?
anonymous
  • anonymous
first of all the parabola definitely opens up indicated by x^2
anonymous
  • anonymous
because it is positive x^2 whereas if it was -x^2 then you would know it is an upside down parabola or opens down.

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anonymous
  • anonymous
I need helping showing work for vertex and x intercept
anonymous
  • anonymous
ok, to find the vertex(turning point) simply we need to factorize the equation first.
anonymous
  • anonymous
do you know how to do that?
anonymous
  • anonymous
And if the vertex is max or min. And no I do not.
anonymous
  • anonymous
vertex is definitely a minimum because the graph is opening upwards.
anonymous
  • anonymous
|dw:1344039832324:dw|
anonymous
  • anonymous
that's an example
anonymous
  • anonymous
it's opening upwards so there's a minimum.
anonymous
  • anonymous
opposite applies so opening downwards, there is a maximum
anonymous
  • anonymous
okay.
anonymous
  • anonymous
guys you mind if I help here too?
anonymous
  • anonymous
The more the better!
anonymous
  • anonymous
look at the graph that has been drawn.
anonymous
  • anonymous
ok, I'll leave it to u @godorovg
anonymous
  • anonymous
no, I could use the help please stay
anonymous
  • anonymous
I can not draw like you
anonymous
  • anonymous
Please help me find the vertex and x intercept!
anonymous
  • anonymous
okay
anonymous
  • anonymous
first I am trying to help with this question only, what do you know about the vertex already?
anonymous
  • anonymous
nothing really.
anonymous
  • anonymous
that is alright, let's take this slow than.
anonymous
  • anonymous
one min
anonymous
  • anonymous
in order to what you are asking we must do something to complete square
anonymous
  • anonymous
let me ask have you ever done this before for finding the vertex?
anonymous
  • anonymous
nope
anonymous
  • anonymous
I am going to use a visual aide here to show you how this done, I went out on the web and found step by step how to do this.
anonymous
  • anonymous
please watch this you tub video here : ► 4:51► 4:51 www.youtube.com/watch?v=niHBt4rkavA
anonymous
  • anonymous
I got it, thank you!
anonymous
  • anonymous
no problem glad I could help out..

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