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anonymous
 4 years ago
For y = x2 − 4x + 3,
Determine if the parabola opens up or down.
State if the vertex will be a maximum or minimum.
Find the vertex.
Find the xintercepts.
Describe the graph of the equation.
PLEASE HELP! Need to finish this..
anonymous
 4 years ago
For y = x2 − 4x + 3, Determine if the parabola opens up or down. State if the vertex will be a maximum or minimum. Find the vertex. Find the xintercepts. Describe the graph of the equation. PLEASE HELP! Need to finish this..

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where do you need help?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first of all the parabola definitely opens up indicated by x^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because it is positive x^2 whereas if it was x^2 then you would know it is an upside down parabola or opens down.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I need helping showing work for vertex and x intercept

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, to find the vertex(turning point) simply we need to factorize the equation first.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you know how to do that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And if the vertex is max or min. And no I do not.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0vertex is definitely a minimum because the graph is opening upwards.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1344039832324:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's opening upwards so there's a minimum.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0opposite applies so opening downwards, there is a maximum

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0guys you mind if I help here too?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0look at the graph that has been drawn.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, I'll leave it to u @godorovg

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no, I could use the help please stay

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I can not draw like you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Please help me find the vertex and x intercept!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first I am trying to help with this question only, what do you know about the vertex already?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is alright, let's take this slow than.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in order to what you are asking we must do something to complete square

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let me ask have you ever done this before for finding the vertex?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am going to use a visual aide here to show you how this done, I went out on the web and found step by step how to do this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0please watch this you tub video here : ► 4:51► 4:51 www.youtube.com/watch?v=niHBt4rkavA

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no problem glad I could help out..
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