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In 1990, walter arfeuille of belgium lifted a 281.5 kg object through a distance of 17.1 cm using only his teeth (a) how much work was done on the object by arfeuille in this lift, assuming the object was lifted at constant speed?

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im thinking \[-\Delta U_{GRAV}?\]
so \[\implies -(281.5)(9.8)(0-0.171)?\] i change this to meters right?

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Other answers:

0.171 is in metres already. I don't get your question.
that multiplication is the answer though..
the given was 17.1 i was confirming that i needed to change that to meters
or do i use 17.1?
ah, yes, it is 0.171 that you need you need to use.
ahh thanks
His work was used to increase potential energy of the weight, therefore you can calculate like W=mgh=281.5x9.81x0.171 J I have heard that the work done later on by his dentist to fix his dentures was quite hard
a follow up question was (b) What total force was exerted on arfeuille's teeth during the lift what does that mean?
The forced exerted was exactly F=mg=281.5 x 9.81 Newtons
It means that a downward force equal to the weight he lifted will be exerted on his teeth (the contact point).
Btw, @CarlosGP, I saw a man on TV lift a 1000kgs (a ton) with his teeth. Jus sayin.
I saw another one make the Statue of Liberty disappear! ;) Can you believe it?
but this was for real. It was on 'Superhuman' on the DISCOVERY CHANNEL!
I have to see under which conditions was the test carried out. I am not too sure neck muscles can stand that force
I'll try to find a video..
@rajathsbhat, I would appreciate it! Thanks!
so for (b) it's just gravitational force?
yes. Sorry, I was busy searching for that vid.
haha lol...
and yes, it is the gravitational force.

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