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3x^3+2x^2 +X+5 the derivative
evalauate y' when x=3 need a little help bit rusty
 one year ago
 one year ago
3x^3+2x^2 +X+5 the derivative evalauate y' when x=3 need a little help bit rusty
 one year ago
 one year ago

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godorovgBest ResponseYou've already chosen the best response.1
in order to the first you lower the power by one like this 3x^2+2x^1+5 that is der right?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
you also have to divide by the original index
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
you divide by 3 because of 3x^3
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
so if I divide by 3, than that would make this x^2 instead of 3x^2 I am on the right track?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
opps ive got mixed up
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
y' 3x^2 is X^2 right?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
i should have said times by the index \[y(x)=ax^n\qquad\Rightarrow\qquad y'(x)=anx^{n1}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
so sorry if i confused you
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
so times by index makes 3x^3 Y' 6x^2 right?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
not quite \[y(x)=3x^3\qquad y'(x)=3\times3x^2\]
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
here is what I know y' when doing this you lower the power by one and something??
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
when taking the derivative multiply by the power and then lower the power
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
so you are telling that power before lowering divide to y'
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
like this 4x^3 so that would be 'y 4 right?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
i ment times when i said divide originally , dont divide when taking the derivative
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
can we start over plz..
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[y(x)=ax^n\qquad\Rightarrow\qquad y'(x)=n\times ax^{n1}\] \[y(x)=4x^2\qquad\Rightarrow\qquad y'(x)=2\times 4x^{21}\]
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
okay so the power is what you are times before lowering the power?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
so for another example 10X^5 y'(x) 50x^4
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
you got it \(\checkmark\)
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
so back to the problem now
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[y(x)=3x^3+2x^2 +x+5\]\[y'(x)=\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
not quite, note that \[x=x^1\]\[5=5x^0\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
ok lets do this one term at a time \[(3x^3)^\prime=\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
right, now \[(2x^2)^\prime=\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
you have the first two terms right,
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[f(x)=x=x^1\] \[f^\prime(x)=1\times x^{11}=x^0=1\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
the derivative of the last term \[g(x)=5=5x^0\] \[g^\prime(x)=0\times 5x^{01}=\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
yeah the derivative of a constant is always zero
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
so the end number unless it has a power drop off?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[f(x)=x^2+5\qquad f'(x)=2x\]\[g(x)=x^2+9\qquad g'(x)=2x\]\[h(x)=x^2−71\qquad f'(x)=2x\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
that last one is ment to be h'
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
cool love it so far because in math you can't drop anything, in calc 1 you can this is way cool..
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
do you have time to do one more?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
yeah can you get the answer to you original question now?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[y(x)=3x^3+2x^2 +x+5\] \[y~'(x)=\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[\Large\color\red\checkmark\]
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
okay any other tips here?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[y'(x)=\frac{\text dy(x)}{\text dx}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
its just a different notation, they men the same thing
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
the second has a bit more information because it explicitly say that we are to take the derivative of the function with respect to x, ie we look at the power of the x terms,
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
so the power on the is 1 right?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
just to let know, I am in college not high school
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[y(x)=x=x^1\] \[\frac{\text dy(x)}{\text dx}=y'(x)=1\times x^{11}=x^0=1\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
im not sure what you mean by this dx(x)^1?dx
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
I meant to use / not?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dx(x)^1/dx \[=\large \frac{\text d(x)^1}{\text dx}\]?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
yes that is what I meant to type
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[\frac{\text d(x)}{\text dx}=\frac{\text d(x^1)}{\text dx}=1\times x^0=1\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
im not sure if i am answer your question?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
okay now for the last question here how do this with y"(x) sin
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
should we evaluate y' in the first question when x=3 before that?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
y'(x) 9x^2+4x+1 so plug in 3 so we have y'(x) 9x^2 (3) +4x(3) +1 which is y'(x) 27x^2+ 12X +1
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[y(x)=3x^3+2x^2+x+5\] \[y'(x)=9x^2+4x+1\] \[y'(3)=9(3)^2+4(3)+1=9\times3\times3+4\times3+1\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
when you evaluate a function at a particular x value you substitute this value for x in the equation, there should be no x in left when evaluated
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
sorry i mess me up by not putting the like this (3)^2
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
so the answer is F'(3) 81x^2 + 12X +1
 one year ago
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