anonymous
  • anonymous
The number of real roots of eq 3x^5 + 10x^3 + 30x + 7 =0 ?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@mukushla @experimentX @Ishaan94
anonymous
  • anonymous
Solve it bro
anonymous
  • anonymous
Any clue @alanli123

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Or graph it?
anonymous
  • anonymous
then look at x intercepts?
anonymous
  • anonymous
i wabt to solve this manually not by graph
anonymous
  • anonymous
Ok use the rational roots theorem and plug in possible root values
anonymous
  • anonymous
wat is that
anonymous
  • anonymous
bro how old are u
anonymous
  • anonymous
my guess is only one. and that one root should be negative.
anonymous
  • anonymous
i used descartes rule of signs.
anonymous
  • anonymous
hw u guys are using that rule can u teach me that @Ishaan94
anonymous
  • anonymous
i think that method is very easy!
anonymous
  • anonymous
i can link you, http://mathworld.wolfram.com/DescartesSignRule.html. yes it's quite easy.
anonymous
  • anonymous
it says file not found @Ishaan94
anonymous
  • anonymous
nop i got it
anonymous
  • anonymous
haha really? try again, http://mathworld.wolfram.com/DescartesSignRule.html
anonymous
  • anonymous
@Ishaan94 that helps a lot.....i am happy that i learnt new concept ....thxx
anonymous
  • anonymous
since there is no change of sign it does not have any + ve roots
anonymous
  • anonymous
is that correct
anonymous
  • anonymous
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.