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Yahoo!Best ResponseYou've already chosen the best response.0
@mukushla @experimentX @Ishaan94
 one year ago

alanli123Best ResponseYou've already chosen the best response.0
then look at x intercepts?
 one year ago

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i wabt to solve this manually not by graph
 one year ago

alanli123Best ResponseYou've already chosen the best response.0
Ok use the rational roots theorem and plug in possible root values
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.3
my guess is only one. and that one root should be negative.
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.3
i used descartes rule of signs.
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
hw u guys are using that rule can u teach me that @Ishaan94
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
i think that method is very easy!
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.3
i can link you, http://mathworld.wolfram.com/DescartesSignRule.html. yes it's quite easy.
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
it says file not found @Ishaan94
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.3
haha really? try again, http://mathworld.wolfram.com/DescartesSignRule.html
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
@Ishaan94 that helps a lot.....i am happy that i learnt new concept ....thxx
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
since there is no change of sign it does not have any + ve roots
 one year ago
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