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moha_10 Group TitleBest ResponseYou've already chosen the best response.1
dw:1349270188044:dw
 one year ago

telliott99 Group TitleBest ResponseYou've already chosen the best response.0
If I'm reading this right, you have two resistors in series followed by three in parallel, with all the individual resistances known (2.5, 0.25, then 4, 5 and 2 ohms). Voltage is given, so the problem is to solve for the current? You need to find Req for the parallel resistors. The formula is: \[\frac{1}{R_{eq} }= \sum \frac{1}{R_i}\] Does this help?
 one year ago

moha_10 Group TitleBest ResponseYou've already chosen the best response.1
@telliott99 thx
 one year ago

moha_10 Group TitleBest ResponseYou've already chosen the best response.1
how is will be the result
 one year ago

telliott99 Group TitleBest ResponseYou've already chosen the best response.0
Do I have the correct numbers? Is it 4 or 40?
 one year ago

niki Group TitleBest ResponseYou've already chosen the best response.0
{5240}+2.5 0.25=4.129ohm to find i2,i2=[(405)/{(405)+2}]*100/4.129=16.56(approx)
 one year ago

niki Group TitleBest ResponseYou've already chosen the best response.0
check the ans
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
@moha_10 hi check that lesson for better understanding of resistors in parallel http://utwired.engr.utexas.edu/rgd1/lesson05.cfm
 one year ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
u can also use ORCAD to solve that!
 one year ago
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