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anonymous
 3 years ago
plz help look at pic
anonymous
 3 years ago
plz help look at pic

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349270188044:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If I'm reading this right, you have two resistors in series followed by three in parallel, with all the individual resistances known (2.5, 0.25, then 4, 5 and 2 ohms). Voltage is given, so the problem is to solve for the current? You need to find Req for the parallel resistors. The formula is: \[\frac{1}{R_{eq} }= \sum \frac{1}{R_i}\] Does this help?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how is will be the result

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do I have the correct numbers? Is it 4 or 40?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0{5240}+2.5 0.25=4.129ohm to find i2,i2=[(405)/{(405)+2}]*100/4.129=16.56(approx)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@moha_10 hi check that lesson for better understanding of resistors in parallel http://utwired.engr.utexas.edu/rgd1/lesson05.cfm

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u can also use ORCAD to solve that!
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