Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Open

moha_10 Group TitleBest ResponseYou've already chosen the best response.1
dw:1349270188044:dw
 2 years ago

telliott99 Group TitleBest ResponseYou've already chosen the best response.0
If I'm reading this right, you have two resistors in series followed by three in parallel, with all the individual resistances known (2.5, 0.25, then 4, 5 and 2 ohms). Voltage is given, so the problem is to solve for the current? You need to find Req for the parallel resistors. The formula is: \[\frac{1}{R_{eq} }= \sum \frac{1}{R_i}\] Does this help?
 2 years ago

moha_10 Group TitleBest ResponseYou've already chosen the best response.1
@telliott99 thx
 2 years ago

moha_10 Group TitleBest ResponseYou've already chosen the best response.1
how is will be the result
 2 years ago

telliott99 Group TitleBest ResponseYou've already chosen the best response.0
Do I have the correct numbers? Is it 4 or 40?
 2 years ago

niki Group TitleBest ResponseYou've already chosen the best response.0
{5240}+2.5 0.25=4.129ohm to find i2,i2=[(405)/{(405)+2}]*100/4.129=16.56(approx)
 2 years ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
@moha_10 hi check that lesson for better understanding of resistors in parallel http://utwired.engr.utexas.edu/rgd1/lesson05.cfm
 2 years ago

ali110 Group TitleBest ResponseYou've already chosen the best response.0
u can also use ORCAD to solve that!
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.