anonymous
  • anonymous
plz help look at pic
MIT 6.002 Circuits and Electronics, Spring 2007
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1349270188044:dw|
anonymous
  • anonymous
If I'm reading this right, you have two resistors in series followed by three in parallel, with all the individual resistances known (2.5, 0.25, then 4, 5 and 2 ohms). Voltage is given, so the problem is to solve for the current? You need to find Req for the parallel resistors. The formula is: \[\frac{1}{R_{eq} }= \sum \frac{1}{R_i}\] Does this help?
anonymous
  • anonymous
@telliott99 thx

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
how is will be the result
anonymous
  • anonymous
Do I have the correct numbers? Is it 4 or 40?
anonymous
  • anonymous
{5||2||40}+2.5 0.25=4.129ohm to find i2,i2=[(40||5)/{(40||5)+2}]*100/4.129=16.56(approx)
anonymous
  • anonymous
check the ans
anonymous
  • anonymous
@moha_10 hi check that lesson for better understanding of resistors in parallel http://utwired.engr.utexas.edu/rgd1/lesson05.cfm
anonymous
  • anonymous
u can also use ORCAD to solve that!

Looking for something else?

Not the answer you are looking for? Search for more explanations.