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asnaseer Group TitleBest ResponseYou've already chosen the best response.2
it is making use of the rule:\[a\times a^n=a^{n+1}\]
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
can you see how?
 2 years ago

wach Group TitleBest ResponseYou've already chosen the best response.0
Not really. Could you put the equation into that rule? I think I'l be able to understand, then.
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
ok, first of all how can you simplify the left hand side of your expression?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
e.g. a + a + a = ?
 2 years ago

wach Group TitleBest ResponseYou've already chosen the best response.0
3(3^x), right?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
now apply the rule
 2 years ago

waleed_imtiaz Group TitleBest ResponseYou've already chosen the best response.0
Lets see this question like this.... :) let 3^x=y..... the above equation is....... 3^x + 3^x + 3^x = 3^x *3 y+y+y=y(3) 3y=3y...... It is an identity...... :DA
 2 years ago

wach Group TitleBest ResponseYou've already chosen the best response.0
a(a^n) = a^n+1 3(3^x) = 3^x+1 Aa. If I may ask, how does the rule work/make sense?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
e.g.:\[a\times a^3=a\times(a\times a\times a)=a\times a\times a\times a=a^4\]
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
and 4 = 3 + 1
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
the general rule here is:\[a^m\times a^n=a^{m+n}\]
 2 years ago

wach Group TitleBest ResponseYou've already chosen the best response.0
Ohhhh. That makes complete sense when worked out. Thank you so much for helping me with this concept, asnaseer!
 2 years ago
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