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asnaseer Group TitleBest ResponseYou've already chosen the best response.2
it is making use of the rule:\[a\times a^n=a^{n+1}\]
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
can you see how?
 one year ago

wach Group TitleBest ResponseYou've already chosen the best response.0
Not really. Could you put the equation into that rule? I think I'l be able to understand, then.
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
ok, first of all how can you simplify the left hand side of your expression?
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
e.g. a + a + a = ?
 one year ago

wach Group TitleBest ResponseYou've already chosen the best response.0
3(3^x), right?
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
now apply the rule
 one year ago

waleed_imtiaz Group TitleBest ResponseYou've already chosen the best response.0
Lets see this question like this.... :) let 3^x=y..... the above equation is....... 3^x + 3^x + 3^x = 3^x *3 y+y+y=y(3) 3y=3y...... It is an identity...... :DA
 one year ago

wach Group TitleBest ResponseYou've already chosen the best response.0
a(a^n) = a^n+1 3(3^x) = 3^x+1 Aa. If I may ask, how does the rule work/make sense?
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
e.g.:\[a\times a^3=a\times(a\times a\times a)=a\times a\times a\times a=a^4\]
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
and 4 = 3 + 1
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.2
the general rule here is:\[a^m\times a^n=a^{m+n}\]
 one year ago

wach Group TitleBest ResponseYou've already chosen the best response.0
Ohhhh. That makes complete sense when worked out. Thank you so much for helping me with this concept, asnaseer!
 one year ago
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