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madison712
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You have 4 math books, 3 english books, and six science books. If you select books at random what is the probability of picking 3 english books?
 2 years ago
 2 years ago
madison712 Group Title
You have 4 math books, 3 english books, and six science books. If you select books at random what is the probability of picking 3 english books?
 2 years ago
 2 years ago

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Ganpat Group TitleBest ResponseYou've already chosen the best response.1
how many books u have ??
 2 years ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
@madison712 : lets do it together.. hope u dont mind..
 2 years ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
add all them together.. you will get total number of books..
 2 years ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
you have total of 6+4+3 = 13 books.. now, picking book and it shd be English.. so u have 3 English books.. So the probability would be 13C3...
 2 years ago

xoya Group TitleBest ResponseYou've already chosen the best response.0
even i think you are right :)
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
probabilities aint greater than 1
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i think a hypergeometric probability might be more condusive
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[\large\frac{\binom{M}{k}\binom{NM}{nk}}{\binom{N}{n}}\]
 2 years ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
oh sorry.. small mistake..
 2 years ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
it should be 3/13...
 2 years ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
@amistre64 : ?? what say ?
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
or one way of looking at it might be if we put all 13 books into a box; the probability of picking an E in the first go around is: 3/13 out of the remaining 12 books ; the probability of picking an E in the 2nd go around is: 2/12 out of the remaining 11 books ; the probability of picking an E in the 3rd go around is: 1/11 P(A and B and C) = P(A) * P(B) * P(C)
 2 years ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
hmmm, agree.. i thought, just one book.. thnx !!!
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
youre welcome
 2 years ago
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