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madison712
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You have 4 math books, 3 english books, and six science books. If you select books at random what is the probability of picking 3 english books?
 one year ago
 one year ago
madison712 Group Title
You have 4 math books, 3 english books, and six science books. If you select books at random what is the probability of picking 3 english books?
 one year ago
 one year ago

This Question is Open

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
how many books u have ??
 one year ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
@madison712 : lets do it together.. hope u dont mind..
 one year ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
add all them together.. you will get total number of books..
 one year ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
you have total of 6+4+3 = 13 books.. now, picking book and it shd be English.. so u have 3 English books.. So the probability would be 13C3...
 one year ago

xoya Group TitleBest ResponseYou've already chosen the best response.0
even i think you are right :)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
probabilities aint greater than 1
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i think a hypergeometric probability might be more condusive
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[\large\frac{\binom{M}{k}\binom{NM}{nk}}{\binom{N}{n}}\]
 one year ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
oh sorry.. small mistake..
 one year ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
it should be 3/13...
 one year ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
@amistre64 : ?? what say ?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
or one way of looking at it might be if we put all 13 books into a box; the probability of picking an E in the first go around is: 3/13 out of the remaining 12 books ; the probability of picking an E in the 2nd go around is: 2/12 out of the remaining 11 books ; the probability of picking an E in the 3rd go around is: 1/11 P(A and B and C) = P(A) * P(B) * P(C)
 one year ago

Ganpat Group TitleBest ResponseYou've already chosen the best response.1
hmmm, agree.. i thought, just one book.. thnx !!!
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
youre welcome
 one year ago
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