Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

madison712

  • 2 years ago

You have 4 math books, 3 english books, and six science books. If you select books at random what is the probability of picking 3 english books?

  • This Question is Open
  1. Ganpat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how many books u have ??

  2. Ganpat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @madison712 : lets do it together.. hope u dont mind..

  3. xoya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    may be 13 :/

  4. Ganpat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    add all them together.. you will get total number of books..

  5. Ganpat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you have total of 6+4+3 = 13 books.. now, picking book and it shd be English.. so u have 3 English books.. So the probability would be 13C3...

  6. xoya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    even i think you are right :)

  7. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    probabilities aint greater than 1

  8. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i think a hypergeometric probability might be more condusive

  9. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\large\frac{\binom{M}{k}\binom{N-M}{n-k}}{\binom{N}{n}}\]

  10. Ganpat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh sorry.. small mistake..

  11. Ganpat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it should be 3/13...

  12. Ganpat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @amistre64 : ?? what say ?

  13. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    or one way of looking at it might be if we put all 13 books into a box; the probability of picking an E in the first go around is: 3/13 out of the remaining 12 books ; the probability of picking an E in the 2nd go around is: 2/12 out of the remaining 11 books ; the probability of picking an E in the 3rd go around is: 1/11 P(A and B and C) = P(A) * P(B) * P(C)

  14. Ganpat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hmmm, agree.. i thought, just one book.. thnx !!!

  15. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    youre welcome

  16. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.