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rudedawg

  • 3 years ago

having trouble figuring out how to solve this. e^(x-5)=(1/e^4)^(x+2)

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  1. GOODMAN
    • 3 years ago
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    Try taking the ln of each side so you can get the exponents down.

  2. rudedawg
    • 3 years ago
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    so we have (x-5)ln e=(x+2)ln (1/4e^4) after this what is our next step?

  3. TuringTest
    • 3 years ago
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    you have to be careful in simplification here\[(x^a)^b=x^{ab}\]and\[\frac1{x^a}=x^{-a}\]so\[\large (\frac1{e^4})^{x+2}=(e^{-4})^{x+2}=e^{-4(x+2)}\]now try with the log...

  4. rudedawg
    • 3 years ago
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    just got it. thx. mental block

  5. rudedawg
    • 3 years ago
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    -3/5?

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