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rudedawg
having trouble figuring out how to solve this. e^(x-5)=(1/e^4)^(x+2)
Try taking the ln of each side so you can get the exponents down.
so we have (x-5)ln e=(x+2)ln (1/4e^4) after this what is our next step?
you have to be careful in simplification here\[(x^a)^b=x^{ab}\]and\[\frac1{x^a}=x^{-a}\]so\[\large (\frac1{e^4})^{x+2}=(e^{-4})^{x+2}=e^{-4(x+2)}\]now try with the log...
just got it. thx. mental block