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Circle P has a radius of 8 units with center P at (2, -1). Which equation defines circle P?

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equation of a circle is \[(x-h)^2 + (y-k)^2 = r^2\] where (h,k) is the center and r is the raidus does that help
(x + 2)2 + (y – 1)2 = 64 (x – 2)2 + (y + 1)2 = 64 (x – 2)2 + (y + 1)2 = 8 (x + 2)2 + (y – 1)2 = 8
so does your flaunting of the choices mean you didnt get what i said?

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Other answers:

Yeah. Haha because none of them matched the - + - pattern
- - means +
^does that make sense?
Yes I know that.
so what's your problem then?
maybe if i show you a demo...
I have to choose which of those defines P.
the center of a circle is (3, -4) and radius is 5 he equation would be \[(x- 3)^2 + (y - -4)^2 = 5^2\] \[\implies (x-3)^2 + (y+4)^2 = 25\] got the idea now?
OH I think so, thanks :)
welcome ^_^
The solution is: (x-2)^2+(y+1)^2=64

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