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computergeek123 Group Title

Circle P has a radius of 8 units with center P at (2, -1). Which equation defines circle P?

  • 2 years ago
  • 2 years ago

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  1. lgbasallote Group Title
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    equation of a circle is \[(x-h)^2 + (y-k)^2 = r^2\] where (h,k) is the center and r is the raidus does that help

    • 2 years ago
  2. computergeek123 Group Title
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    (x + 2)2 + (y – 1)2 = 64 (x – 2)2 + (y + 1)2 = 64 (x – 2)2 + (y + 1)2 = 8 (x + 2)2 + (y – 1)2 = 8

    • 2 years ago
  3. lgbasallote Group Title
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    so does your flaunting of the choices mean you didnt get what i said?

    • 2 years ago
  4. computergeek123 Group Title
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    Yeah. Haha because none of them matched the - + - pattern

    • 2 years ago
  5. lgbasallote Group Title
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    - - means +

    • 2 years ago
  6. lgbasallote Group Title
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    ^does that make sense?

    • 2 years ago
  7. computergeek123 Group Title
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    Yes I know that.

    • 2 years ago
  8. lgbasallote Group Title
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    so what's your problem then?

    • 2 years ago
  9. lgbasallote Group Title
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    maybe if i show you a demo...

    • 2 years ago
  10. computergeek123 Group Title
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    I have to choose which of those defines P.

    • 2 years ago
  11. lgbasallote Group Title
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    the center of a circle is (3, -4) and radius is 5 he equation would be \[(x- 3)^2 + (y - -4)^2 = 5^2\] \[\implies (x-3)^2 + (y+4)^2 = 25\] got the idea now?

    • 2 years ago
  12. computergeek123 Group Title
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    OH I think so, thanks :)

    • 2 years ago
  13. lgbasallote Group Title
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    welcome ^_^

    • 2 years ago
  14. efremmc Group Title
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    The solution is: (x-2)^2+(y+1)^2=64

    • 2 years ago
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