computergeek123
Circle P has a radius of 8 units with center P at (2, -1). Which equation defines circle P?
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lgbasallote
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equation of a circle is \[(x-h)^2 + (y-k)^2 = r^2\]
where (h,k) is the center and r is the raidus
does that help
computergeek123
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(x + 2)2 + (y – 1)2 = 64
(x – 2)2 + (y + 1)2 = 64
(x – 2)2 + (y + 1)2 = 8
(x + 2)2 + (y – 1)2 = 8
lgbasallote
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so does your flaunting of the choices mean you didnt get what i said?
computergeek123
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Yeah. Haha because none of them matched the - + - pattern
lgbasallote
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- - means +
lgbasallote
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^does that make sense?
computergeek123
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Yes I know that.
lgbasallote
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so what's your problem then?
lgbasallote
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maybe if i show you a demo...
computergeek123
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I have to choose which of those defines P.
lgbasallote
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the center of a circle is (3, -4) and radius is 5
he equation would be \[(x- 3)^2 + (y - -4)^2 = 5^2\]
\[\implies (x-3)^2 + (y+4)^2 = 25\]
got the idea now?
computergeek123
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OH I think so, thanks :)
lgbasallote
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welcome ^_^
efremmc
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The solution is: (x-2)^2+(y+1)^2=64