anonymous
  • anonymous
Can Someone Please Help!! I don;t know what I'm doing wrong!! (The question and my work is attached) http://assets.openstudy.com/updates/attachments/501ec235e4b0be43870f0563-ranyai12-1344193091852-math216new.jpg http://assets.openstudy.com/updates/attachments/501ec235e4b0be43870f0563-ranyai12-1344193118071-img_07531.jpg
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@Spacelimbus
anonymous
  • anonymous
hmm I can't see the error myself yet, my only guess could be with the fixated values.
anonymous
  • anonymous
i know that the 3 is wrong but idk why

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anonymous
  • anonymous
The Jacobian Matrix looks right to me too, have you tried with different fixated values? other critical points I mean, I see you have found three of them.
anonymous
  • anonymous
yea and they all seem to be wrong somehow one of the values in the jacobian end up being wrong
anonymous
  • anonymous
so it seems like the critical points are the problem then, not your setup.
anonymous
  • anonymous
\[\Large x'=y \\ \Large y'=3x-3x^3 \] yes?
anonymous
  • anonymous
yea
anonymous
  • anonymous
but my critical points are correct because in a previous question it asked to solve for all the critical points and this was a follow up question
anonymous
  • anonymous
yes I see.
anonymous
  • anonymous
\[\Large J(x,y)=\left[\begin{matrix}0 & 1 \\ -9x^2+3 & 0\end{matrix}\right]\]
anonymous
  • anonymous
I caught my mistake!!!
anonymous
  • anonymous
oh? Mind to share?
anonymous
  • anonymous
I haven't seen it yet.
anonymous
  • anonymous
when i plugged in the critical poiints into the jacobian there was an algebraic error so the jacobian wouldve been 0 1 -6 0
anonymous
  • anonymous
point (1,0) huh?
anonymous
  • anonymous
yea
anonymous
  • anonymous
hmm I understand it for that point, but I am not sure why point (0,0) shouldn't work, if it's in fact a critical point.
anonymous
  • anonymous
because this question is asking for the first critical point we found, which we had to put in order from lowest value ot highest, and so we had to use (-1,0)
anonymous
  • anonymous
Oh I understand, I wasn't aware of that. (-: Well, well done!
anonymous
  • anonymous
Thank you!!!

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