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A) 4x+4y=-4(multi eq 1 with 4)
4x+4y=-4
subtract both eq
we'll get 0 = 0

thats a right ?

wait thats the 4th one so A= 4

or a = 2

B) 2x - 8y = -16(multi eq1 with 2)
2x - 3y = -16
subtracting both eqs
-5y = 0
y=0
x= -8
(-8,0)

A system of eq has no solution

so A= is the 4th one like i said

yes

what bout the other two

can you solve the rest ???

Which system has (1, 3) as the solution?

B system of eq has solution set = (-8,0)

E) x - y = -2
3x - y = 0

that is correct right ?

wait

E) x - y = -2
3x - y = 0
subtracting both eqs
-2x=-2
x= 1
y=3
(1,3)
yes E has solution set (1,3)

Thought so..

is c the last option

so i am right :)

yes :)

then D is the second one

D) 4x + 6y = -12
4x + 6y = 18(multi by 2)
subtract both eqs
0 = -30
so D has infinite solutions