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littlesharaih

  • 3 years ago

The sum of the digits of a two-digit number is 12. If the units digit is 3 times the tens digit, find the number.

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  1. hoblos
    • 3 years ago
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    let a be the units digit and b be the tens digit the number = 10b +a to find a and b we must solve the system a+b =12 a= 3b can you solve it ??

  2. littlesharaih
    • 3 years ago
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    I'm not understanding

  3. hoblos
    • 3 years ago
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    you dont understand the part that the two digit number = 10b + a ??

  4. littlesharaih
    • 3 years ago
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    I don't understand how we start at 10b+a and then we go to a+b=12

  5. hoblos
    • 3 years ago
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    no! these two parts are not related directly.. 10a+b is the general form of any two digits number but a+b =12 is concluded from the given ( The sum of the digits of a two-digit number is 12)

  6. littlesharaih
    • 3 years ago
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    |dw:1344293939890:dw|

  7. littlesharaih
    • 3 years ago
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    is this correct?

  8. hoblos
    • 3 years ago
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    b=3 is correct but then you must replace (b=3) in the equation a+b=12 to get a and then add 10b +a

  9. littlesharaih
    • 3 years ago
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    therefore my answer is 39

  10. hoblos
    • 3 years ago
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    yes it is.. good job :)

  11. littlesharaih
    • 3 years ago
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    thank you!!!

  12. hoblos
    • 3 years ago
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    glad to help :)

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