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ranyai12
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@Spacelimbus

ranyai12
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@TuringTest

sami21
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@ranyai12 you there ?

ranyai12
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yes i am

sami21
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ok

sami21
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you have given piecewise function .first the definition of Laplace is
\[[\Large F(s)=\int\limits\limits_{0}^{\infty}e^{st}f(t)dt\]\]

ranyai12
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sorry openstudy logged me out!

ranyai12
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what values from the graph would we incorporate?

ranyai12
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@sami21 are you still there?

sami21
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yes i am here . openstudy crashed me :( i was typing everything went off :(
let me try again.

Spacelimbus
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OpenStudy is a bit of a pain today, I was opening this question about 20 minutes ago, and by now I am here hehe.

ranyai12
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lol yea i understand it kept on logging me out!

sami21
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it is piece wise function can be written as

ranyai12
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do you get the integration to be (3e^(st))/s

sami21
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yes apply the limits

ranyai12
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and the limits are the s right

sami21
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nopes!! they are for t :P

ranyai12
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oh lol

ranyai12
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ok so the answer would be (3e^(5s)(3e^s1))/s

sami21
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you did a mistake .
first take 3 common also the second one should be e^(2s)

ranyai12
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what do you mean first take 3 common

ranyai12
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so the answer is 3(e^5s/se^2s/s)

sami21
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\[\Large \frac{3}{s}e^{st}_{2}^{5}=\frac{3}{s}[e^{5s}e^{2s}]\]

sami21
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@ranyai12 yes it is just you missed minus sign with the s in the exponent.

ranyai12
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oh ok thank you

sami21
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you 're welcome :)

ranyai12
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it ended up being wrong

ranyai12
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wait nevermind i got it!

ranyai12
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it was right! i plugged it in wrong

Spacelimbus
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(: !

sami21
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you must have missed minus sign with 3 :P

ranyai12
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I did! lol