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Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2Have you differentiated it?

margejean
 2 years ago
Best ResponseYou've already chosen the best response.0No I have not. How do you do that?

margejean
 2 years ago
Best ResponseYou've already chosen the best response.0No I havent taken that class yet. This is AP Stats.

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2Statistics..? This is Calculus. Or is there an algebra method to solve this?

margejean
 2 years ago
Best ResponseYou've already chosen the best response.0This class is AP Stats but U guess it is just basic math review. (Algebra)

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2Hm, I don't know the algebra method.. maybe @lgbasallote might know

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0i dont know algebra sorry

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1when the first derivative is zero, there will be a minimum or maximum

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2is the algebra method got to do something with the vertex (b)/2a?

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1yes Mimi_x3, that formula will give us the xcoordinate of the vertex,

margejean
 2 years ago
Best ResponseYou've already chosen the best response.0um i am not sure, but i think if I use (b)/2a the answer would be 5 or 2.5?

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1the value is the f(x), so sub x=b/2a into f f(b/2a)= to get the value of f(x) that the minimum

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2Vertex: \[\large \left(\frac{b}{2a},a\left(\frac{b}{2a}\right)^{2}+b\left(\frac{b}{2a}\right)+C\right) \] a> 0 => its a min a<0 => its a max. however, the calculus method is more nicer :)

margejean
 2 years ago
Best ResponseYou've already chosen the best response.0I got 2.5.i hope its right. thank you for helping.
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