Ayeshaafzal
Differentiate x^2 surd x
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Mimi_x3
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\[x^2 \sqrt{x}\]?
lgbasallote
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\[\Large x^2 \sqrt x \implies x^2 \times x^{1/2} \implies x^{2 + 1/2} \implies x^{5/2}\]
does that help?
lgbasallote
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@Ayeshaafzal you still here?
Ayeshaafzal
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But the answer says 5 root x3 over 2
lgbasallote
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correct...
lgbasallote
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i only said the equivalent of \[x \sqrt x\] i never said it was the answer...
lgbasallote
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you have to take the derivative of \[x^{5/2}\] use power rule
Ayeshaafzal
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X^3*
lgbasallote
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you know how to use power rule right?
Ayeshaafzal
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No i forgot
lgbasallote
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\[\huge \frac{d}{dx} (x^n) \implies nx^{n-1}\]
remember now?
Ayeshaafzal
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Ohhh i get it thnx
lgbasallote
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welcome ^_^
Ayeshaafzal
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I am still not getting the answer
lgbasallote
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did you get \[\huge\frac{d}{dx} (x^{5/2}) \implies \frac 52 x^{\frac 52 - 1}\]
Ayeshaafzal
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Are we not gonna times by x^2 which is the value of n
lgbasallote
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n is 5/2
lgbasallote
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the form is x^n remember? n is the exponent...in this case it's 5/2
lgbasallote
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for example.. derivative of x^3 is 3x^(3-1) or 3x^2
derivative of x^4 is 4x^(4-1) or 4x^3
derivative of x^2 is 2x^(2-1) or 2x^1 or simply 2x
getting the idea now?
Ayeshaafzal
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Got it 5*x^3/2 /2= 5 rootx^3 over2
lgbasallote
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right
Ayeshaafzal
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Thank u i am so sorry about my dumbness
lgbasallote
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haha nahh calculus is hard so dont feel bad :D
lgbasallote
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anyway you're welcome :D i have to go sleep now so i wsh you luck in these problems
Ayeshaafzal
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Have a good night