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Ayeshaafzal

  • 2 years ago

Differentiate x^2 surd x

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  1. Mimi_x3
    • 2 years ago
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    \[x^2 \sqrt{x}\]?

  2. lgbasallote
    • 2 years ago
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    \[\Large x^2 \sqrt x \implies x^2 \times x^{1/2} \implies x^{2 + 1/2} \implies x^{5/2}\] does that help?

  3. lgbasallote
    • 2 years ago
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    @Ayeshaafzal you still here?

  4. Ayeshaafzal
    • 2 years ago
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    But the answer says 5 root x3 over 2

  5. lgbasallote
    • 2 years ago
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    correct...

  6. lgbasallote
    • 2 years ago
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    i only said the equivalent of \[x \sqrt x\] i never said it was the answer...

  7. lgbasallote
    • 2 years ago
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    you have to take the derivative of \[x^{5/2}\] use power rule

  8. Ayeshaafzal
    • 2 years ago
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    X^3*

  9. lgbasallote
    • 2 years ago
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    you know how to use power rule right?

  10. Ayeshaafzal
    • 2 years ago
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    No i forgot

  11. lgbasallote
    • 2 years ago
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    \[\huge \frac{d}{dx} (x^n) \implies nx^{n-1}\] remember now?

  12. Ayeshaafzal
    • 2 years ago
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    Ohhh i get it thnx

  13. lgbasallote
    • 2 years ago
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    welcome ^_^

  14. Ayeshaafzal
    • 2 years ago
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    I am still not getting the answer

  15. lgbasallote
    • 2 years ago
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    did you get \[\huge\frac{d}{dx} (x^{5/2}) \implies \frac 52 x^{\frac 52 - 1}\]

  16. Ayeshaafzal
    • 2 years ago
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    Are we not gonna times by x^2 which is the value of n

  17. lgbasallote
    • 2 years ago
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    n is 5/2

  18. lgbasallote
    • 2 years ago
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    the form is x^n remember? n is the exponent...in this case it's 5/2

  19. lgbasallote
    • 2 years ago
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    for example.. derivative of x^3 is 3x^(3-1) or 3x^2 derivative of x^4 is 4x^(4-1) or 4x^3 derivative of x^2 is 2x^(2-1) or 2x^1 or simply 2x getting the idea now?

  20. Ayeshaafzal
    • 2 years ago
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    Got it 5*x^3/2 /2= 5 rootx^3 over2

  21. lgbasallote
    • 2 years ago
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    right

  22. Ayeshaafzal
    • 2 years ago
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    Thank u i am so sorry about my dumbness

  23. lgbasallote
    • 2 years ago
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    haha nahh calculus is hard so dont feel bad :D

  24. lgbasallote
    • 2 years ago
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    anyway you're welcome :D i have to go sleep now so i wsh you luck in these problems

  25. Ayeshaafzal
    • 2 years ago
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    Have a good night

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