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Differentiate x^2 surd x

Mathematics
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\[x^2 \sqrt{x}\]?
\[\Large x^2 \sqrt x \implies x^2 \times x^{1/2} \implies x^{2 + 1/2} \implies x^{5/2}\] does that help?
@Ayeshaafzal you still here?

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Other answers:

But the answer says 5 root x3 over 2
correct...
i only said the equivalent of \[x \sqrt x\] i never said it was the answer...
you have to take the derivative of \[x^{5/2}\] use power rule
X^3*
you know how to use power rule right?
No i forgot
\[\huge \frac{d}{dx} (x^n) \implies nx^{n-1}\] remember now?
Ohhh i get it thnx
welcome ^_^
I am still not getting the answer
did you get \[\huge\frac{d}{dx} (x^{5/2}) \implies \frac 52 x^{\frac 52 - 1}\]
Are we not gonna times by x^2 which is the value of n
n is 5/2
the form is x^n remember? n is the exponent...in this case it's 5/2
for example.. derivative of x^3 is 3x^(3-1) or 3x^2 derivative of x^4 is 4x^(4-1) or 4x^3 derivative of x^2 is 2x^(2-1) or 2x^1 or simply 2x getting the idea now?
Got it 5*x^3/2 /2= 5 rootx^3 over2
right
Thank u i am so sorry about my dumbness
haha nahh calculus is hard so dont feel bad :D
anyway you're welcome :D i have to go sleep now so i wsh you luck in these problems
Have a good night

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