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ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
Confused on b(ii)
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
I'm not sure what to do.
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
I have to find u somehow I reckon, not 100% though.
 2 years ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
Hmm I believe you just have to show that the identity is valid, because the roots are identical.
 2 years ago

colorful Group TitleBest ResponseYou've already chosen the best response.0
pretty similar to the part before it
 2 years ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
But I will try first.
 2 years ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
the other solution will have an additional x infront of it I am not mistaken.
 2 years ago

colorful Group TitleBest ResponseYou've already chosen the best response.0
juts plug it in and see what happens
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
http://en.wikipedia.org/wiki/Reduction_of_order
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
If it's double roots then yes there's extra x in the solution.
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
I'm still not sure what should I do first.
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
I don't know what u is.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
assume that \( x(t) = u(t) x_1(t) \) is another solution ... find the value of u(t) ... so that you have complete solution.
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
Still lost...
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
@experimentX I genuinely don't know where to start.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
i think there is an example in the wikipedia ... in the link i posted above.
 2 years ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
If I understand this problem then they just want you to check what happens if you substitute back their provided result. I believe their are trying to introduce you to the method of Reduction of Order You will get a result in the form of \[ \Large u(x)=d_1x+d_2 \] where \(d_1, d_2\) are constant. The second solution is of the form \[ \Large y_2(x)=u(x)e^{\frac{x}{2}}\] So you can use superposition to get the general solution.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
dw:1344360084786:dw
 2 years ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
Note that \[ \Large 4r^24r+1=0 \] Has a discriminant of zero.
 2 years ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
Pardon me if I was interrupting something in here, OpenStudy lags horribly for me today so I hit the post button before it crashes me again (:
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
and how does that prove it equals 0?
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
Yeah it pretty bad this week
 2 years ago

ironictoaster Group TitleBest ResponseYou've already chosen the best response.0
What I understand so far, we need to sub ux into equation 4
 2 years ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
\[4\left( u''e^{\frac{t}{2}} + \frac{1}{2}e^{\frac{t}{2}}u' + \frac{1}{4}e^{\frac{t}{2}}u + \frac{1}{2}u'e^{\frac{t}{2}}\right) 4 \left(u' e^{\frac{t}{2}}+ \frac{1}{2}e^{\frac{t}{2}}u \right)+ ue^{\frac{t}{2}}=0\]
 2 years ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.0
Divide by \( \large e^{\frac{t}{2}} \) and then see what happens when you bring it all together.
 2 years ago
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