anonymous
  • anonymous
Algebra II help ! (picture) What did I do wrong..? I always thought at the bottom, where n=? you used the number that the sequence started with, which in this case was -5 & then to the right of the E shape went the general term. Where have I messed up?
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
if you are going from -5 to inf, the first of sequence would be 25
anonymous
  • anonymous
does that make sense? so the series shouldn't start from -5

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anonymous
  • anonymous
It kind of does, I suppose. How do you get that? Just by multiplying -5 by itself? & sorry it took me so long to respond, my internet is not getting along with this site.. grr.
anonymous
  • anonymous
the site is going through some upgrading and maintenance so it's no biggie - now, you should first look at the bounds of summation which is to infinity indicating it's going positively up. so when you have it set from -5 to positive infinity, you are going from -5, -4, -3...
anonymous
  • anonymous
if you put that as n into the equation and see what values you get, it would be more clear for you
anonymous
  • anonymous
so on that note, you should consider changing lower bound of summation with what you have as summation equation
anonymous
  • anonymous
So @msayer3 what your saying is that I should put what is on the right of the E looking thing should go on the bottom? But I thought that was the general term? & I thought the general term went to the side?
anonymous
  • anonymous
& sorry for all the questions..
anonymous
  • anonymous
Umn, I would disagree with msayer. The upper term is not the value of the out put but the value of n. n is the index of the term. So in the example; the index of -10 is 2 and the index of -20 is four. You would want |dw:1344369052834:dw|. The E thing is a capital sigma. Look up big-sigma notation on wikipedia for more.
anonymous
  • anonymous
no, what you have in the right side of summation sign looks correct. Just consider changing n = -5 statement which is what's called the lower bound of summation
anonymous
  • anonymous
@lhm that's where I was getting at
anonymous
  • anonymous
sorry i get my terminologies confused
anonymous
  • anonymous
Wait, so what does all that mean?
anonymous
  • anonymous
so simply, your index term for summation is starting at wrong point
anonymous
  • anonymous
& that is my bottom number, right?
anonymous
  • anonymous
Ah. msayer would be right if you were doing something like sum all the values from 1 to 10 (where it would have just 10 above and i=1 below and i on the right).
anonymous
  • anonymous
@Ihm i think we are thinking the exact same thing
anonymous
  • anonymous
I just reread your first statement. I think so too. >.<
anonymous
  • anonymous
Okay, since y'all know are on the same page now, Lol, what did I do wrong...?
anonymous
  • anonymous
As msayer said, your index term is off. Try expanding the sum a bit like this:\[-5*1+-5*2+-5*3...\] where 1,2,3,etc are values of n. Remember that n increases by 1 each step. Here's the layout: \[\sum_{starting-index}^{ending-index} whatever*index\] Try playing around with the starting index. There rest of what you have is fine.
anonymous
  • anonymous
Okay, but what should I try? Like there has to be a method to the madness.
anonymous
  • anonymous
@msayer3 @Ihm Not to bug y'all, but I don't know what to try
anonymous
  • anonymous
Wait. are you summing the terms in the list or just producing the list?
anonymous
  • anonymous
Just producing the list? I'm honestly not sure. I don't have to add anything so I assume make a list.. Does that make sense/answer your question..?
anonymous
  • anonymous
Ok. (I find the question oddly worded). Either way you can look at it like this: make some of the series and write the indexes underneath each term. -5,-10,-15,-20,-25 | term | index take the bit to the right of the sigma and plug in the starting index (below the sigma) for n. If it doesn't match the first term, then it's wrong. Just plug in things like -5, 0, 10, and the like. That will show you how changing the starting index will screw with your sum.
anonymous
  • anonymous
If you fill in the index part of the table above, the first index is your starting index.
anonymous
  • anonymous
So by doing this I find out what goes underneath the stigma?
anonymous
  • anonymous
Yes and why it's important.
anonymous
  • anonymous
I'm sorry, I'm still kind of confused... How will plugging in the numbers give me what goes below? Like I thought it was always what you started with, like your starting number. & Thanks for continuing to help me, I really appreciate it. Like you have no idea.
anonymous
  • anonymous
You needn't plug stuff in to find the right answer- it's just something I thought might help you grasp what it is we're doing when we change the starting index. ----- Think of the index (below the sigma) as an address. Each element in the series has its own, unique address. The starting index can be any number but it always points to the first element in the series, the next element will have an address that is one more than the starting index, and so on.
anonymous
  • anonymous
The important thing is the starting index isn't the first number in the series, it's the /address/ of the first number.

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