Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

MathSofiya

Would this be correct? \[f(x)=cos(\frac{(\pi x)}{2}\] Use MacLaurin table \[cosx=\sum_{n=0}^{\infty}(-1)^n\frac{x^{2n}}{(2n)!}\]=\[1-\frac{x^2}{2!}+\frac{x^4}{4!}-frac{x^6}{6}\] \[cos(\frac{(\pi x)}{2})=\sum_{n=0}^{\infty}(-1)^n\frac{\frac{(\pi x)}{2}^{2n}}{(2n)!}\]=\[1-\frac{\frac{(\pi x)}{2}^2}{2!}+\frac{\frac{(\pi x)}{2}^4}{4!}-frac{\frac{(\pi x)}{2}^6}{6}\]

  • one year ago
  • one year ago

  • This Question is Closed
  1. Spacelimbus
    Best Response
    You've already chosen the best response.
    Medals 1

    \[ \Large \left(\frac{\pi x}{2}\right)^{2n} \]

    • one year ago
  2. Spacelimbus
    Best Response
    You've already chosen the best response.
    Medals 1

    The site is a bit dodgy for me today, it keeps reloading and kicking me out so I am not sure if I see the original equation correct.

    • one year ago
  3. MathSofiya
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry about that. The first line should read: \[f(x)=cos(\frac{\pi x}{2})\]

    • one year ago
  4. MathSofiya
    Best Response
    You've already chosen the best response.
    Medals 1

    The second line was meant to be the macLaurin series for cos(x) that I found in my book. \[cosx=\sum_{n=0}^{\infty}(-1)^n\frac{x^{2n}}{(2n)!}=1-\frac{x^2}{2!}+\frac{x^4}{4!}-\frac{x^6}{6!}\]

    • one year ago
  5. MathSofiya
    Best Response
    You've already chosen the best response.
    Medals 1

    the final few lines are what I believe the answer should be. \[cos\left(\frac{\pi x}{2}\right)=\sum_{n=0}^{\infty}(-1)^n\frac{\frac{(\pi x)}{2}^{2n}}{(2n)!}\]

    • one year ago
  6. Spacelimbus
    Best Response
    You've already chosen the best response.
    Medals 1

    Good, so you want to put wherever you see an x, you want to put the following: \[ \Large \left( \frac{\pi x}{2} \right) \] right? because that is your new 'x' which you can substitute into the given equation.

    • one year ago
  7. MathSofiya
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah I think so. That would make. \[1-\frac{\left(\frac{\pi x}{2}\right)^2}{2!}+\frac{\left(\frac{\pi x}{2}\right)^4}{4!}-\frac{\left(\frac{\pi x}{2}\right)^6}{6!}\]

    • one year ago
  8. Spacelimbus
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, exactly! I was confused first, because the way you did \(\LaTeX\) it in your original post it looked like you would take the Exponent \(2n\) only in consideration for the numerator, but you also have to take it in consideration for your denominator - just like you did!

    • one year ago
  9. MathSofiya
    Best Response
    You've already chosen the best response.
    Medals 1

    Thank you! It's kinda difficult typing latex blindly in the Question box to the left.

    • one year ago
  10. Spacelimbus
    Best Response
    You've already chosen the best response.
    Medals 1

    No problem, you did it all right then, I was just making sure that you noticed that (-: And I agree, there should at least be a preview function of the post!

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.